Answer:
1. Based on the given question, 138.03 grams of NO₂ is reacting completely with 18.02 grams of H2O. However, in case when 359 grams of NO₂ is used then the grams of water consumed in the reaction will be,
= 359 × 18.02 / 138.03 = 46.87 grams of water.
2. As mentioned in the given case 138.03 grams of NO₂ generates 126.04 grams of HNO₃. Therefore, 359 grams of NO₂ will produce,
= 359 × 126.04 / 138.03
= 327.81 grams of HNO₃.
3. Based on the given question, 138.04 grams of NO₂ is generating 30.01 grams of NO. Therefore, 359 grams of NO₂ will generate,
= 359 × 30.01 / 138.04
= 78.04 grams of NO.
67.0 Should be th3 answer
