Answer:
I hope this what you had meant ️️
Explanation:
- the surface area of the solute
- the temperature of the solvent, and
- the amount of agitation that occurs when the solute and the solvent are mixed.
In the apparatus of the electrochemical cell, the seawater is an example of an electrolyte.
<h3>What is an electrolyte?</h3>
An electrolyte is a component of the electrochemical cell that is a solution of solvent or water that contains dissolved ions.
The salts of sodium, chloride, and potassium are the main components of seawater and a great electrolyte.
Therefore seawater is an example of an electrolyte.
Learn more about electrolytes here:
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<span>Like if it didn't boil, nothing evaporated, didn't even get warm. You just have to think about it. </span>
Answer:
Explanation:
Here, a balance between attraction between nucleus and electrons, and electron-electron, and nuclei-nuclei repulsion play role.
All chemical bonds are formed by overlapping of orbitals. If the electronegativity of the two elements forming the bond is very different (elements from the 1st ,2nd groups with elements of 7th group) then ionic bond are formed. If the electronegativities are more similar, then overlapping is stronger, and covalent bonds are formed.
Answer : The oxidation state of nitrogen in 
is, (+5)
Explanation :
Rules for the oxidation numbers :
- The oxidation number of a free element is always be zero.
- The oxidation number of a monatomic ion equal to the charge of the ion.
- The oxidation number of Hydrogen (H) is +1.
- The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in the peroxides.
- The oxidation number of a Group 1 element in a compound is +1.
- The oxidation number of a Group 2 element in a compound is +2.
- The oxidation number of a Group 17 element in a binary compound is -1.
- The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
- The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given compound is,
Let the oxidation state of 'N' be, 'x'
Hence, the oxidation state of N is, (+5)
