Answer: 170.9 g
Explanation:
1) Balanced chemical equation:
Fe₂O₃(s) + 6 H₂C₂O₄ (aq) → 2Fe(C₂O₄)₃³⁻ + 3H₂O + 6H⁺(aq)
2) mole ratio:
1mol Fe₂O₃ : 6 mol H₂C₂O₄
3) number of moles of H₂C₂O₄ in the solution
M = n / V ⇒ n = MV = 0.800M × 0.800 liter = 6.40 moles
4) Porportionality
1mol Fe₂O₃ / 6 mol H₂C₂O₄ = x / 6.40 mol H₂C₂O₄
⇒ x = 1.07 mol Fe₂O₃
5) Convert 1.07 mol Fe₂O₃ to grams.
molar mass Fe₂O₃ = 159.69 g/mol
mass in grams = molaer mass × number of moles
mass in grams = 159.69 g/mol × 1.07 mol = 170.9 g
I think it is the first one, the second one, and the fifth one. Hopefully helps :)
Answer:
B. 17.0.
Explanation:
Hello!
In this case, considering that based on the atomic mass of the carbon atom, which means that 1 mole of carbon weights 12.01 grams, we can set up the following proportional factor to compute the moles of carbon in 200.0 grams:
![200.0gC*\frac{1molC}{12.01gC}\\\\17.0molC](https://tex.z-dn.net/?f=200.0gC%2A%5Cfrac%7B1molC%7D%7B12.01gC%7D%5C%5C%5C%5C17.0molC)
Thus, the answer would be B. 17.0.
Best regards!