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4 years ago

What is napping in the picture

Chemistry

1 answer:

Black_prince [1.1K]4 years ago

3 0

The bird ate the white mouse leaving only 2 white dominant mouses which leaves you to them dying and leaving the darker mouses to reproduce

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By definition, a(n) _______acid is any species that can donate a proton. Ammonia has a proton bonded to nitrogen, so ammonia can

pochemuha

Answer:

A Brønsted-Lowry acid.

A Brønsted-Lowry base.

Ammonia is an acceptor of proton.

Explanation:

A Brønsted-Lowry acid is any atom that can donate a proton (H +) to another atom or molecule whereas Brønsted-Lowry base is any species that can accept a proton from another atom or molecule or in other words, a Brønsted-Lowry acid is a proton donor, while on the other hand, a Brønsted-Lowry base is a proton acceptor. The ammonia molecule accepts the hydrogen ion is considered as the Brønsted-Lowry base.

5 0

3 years ago

hi pls I need ASAP. 1 the tubes responsible for the moment of blood from the heart to d other parts of the body is called 2. the

IRISSAK [1]

Answer:

$\large \boxed{\text{1. Veins; 2. 600 W; 3. 45 N}}$

Explanation:

1. Arteries are the tubes responsible for the movement of blood from the heart to other parts of the body.

2. Power

(a) Work performed

w = mgh = 12 kg × 9.807 m·s⁻² × 15 m = 1800 J

(b) Power level

P = w/t = 1800 J/3 s = 600 W

3. Machine load

The formula for mechanical advantage (MA) is

$MA = \dfrac{F_{o}}{ F_{e}}$

where

Fₒ = the force of the object

Fₑ = the force exerted to overcome that of the object

$\begin{array}{rcl}MA & = &\dfrac{F_{o}}{ F_{e}}\\\\6 & = &\dfrac{F_{o}}{ \text{7.5 N}}\\\\F_{o} & = & \text{45 N}\\\end{array}\\\text{The machine can carry a maximum load of $\large \boxed{\textbf{45 N}}$}$

7 0

4 years ago

A voltaic cell consists of a Zn>Zn2+ half-cell and a Ni>Ni2+ half-cell at 25 °C. The initial concentrations of Ni2+ and Zn

nlexa [21]

Answer :

(a) The initial cell potential is, 0.53 V

(b) The cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M is, 0.52 V

(c) The concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V are, 0.01 M and 1.59 M

Explanation :

The values of standard reduction electrode potential of the cell are:

$E^0_{[Ni^{2+}/Ni]}=-0.23V$

$E^0_{[Zn^{2+}/Zn]}=-0.76V$

From this we conclude that, the zinc (Zn) undergoes oxidation by loss of electrons and thus act as anode. Nickel (Ni) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : $Zn\rightarrow Zn^{2+}+2e^-$ $E^0_{[Zn^{2+}/Zn]}=-0.76V$

Reaction at cathode (reduction) : $Ni^{2+}+2e^-\rightarrow Ni$ $E^0_{[Ni^{2+}/Ni]}=-0.23V$

The balanced cell reaction will be,

$Zn(s)+Ni^{2+}(aq)\rightarrow Zn^{2+}(aq)+Ni(s)$

First we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=E^o_{[Ni^{2+}/Ni]}-E^o_{[Zn^{2+}/Zn]}$

$E^o=(-0.23V)-(-0.76V)=0.53V$

(a) Now we have to calculate the cell potential.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = emf of the cell = ?

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(0.100)}{(1.50)}$

$E_{cell}=0.49V$

(b) Now we have to calculate the cell potential when the concentration of $Ni^{2+}$ has fallen to 0.500 M.

New concentration of $Ni^{2+}$ = 1.50 - x = 0.500

x = 1 M

New concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1 = 1.1 M

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Ni^{2+}]}$

Now put all the given values in the above equation, we get:

$E_{cell}=0.53-\frac{0.0592}{2}\log \frac{(1.1)}{(0.500)}$

$E_{cell}=0.52V$

(c) Now we have to calculate the concentrations of $Ni^{2+}$ and $Zn^{2+}$ when the cell potential falls to 0.45 V.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}+x]}{[Ni^{2+}-x]}$

Now put all the given values in the above equation, we get:

$0.45=0.53-\frac{0.0592}{2}\log \frac{(0.100+x)}{(1.50-x)}$

$x=1.49M$

The concentration of $Ni^{2+}$ = 1.50 - x = 1.50 - 1.49 = 0.01 M

The concentration of $Zn^{2+}$ = 0.100 + x = 0.100 + 1.49 = 1.59 M

5 0

4 years ago

Changing atmospheric conditions, like increasing carbon dioxide content, might possibly _____.

kobusy [5.1K]

<span>Changing atmospheric conditions, like increasing carbon dioxide content, might possibly increase the risk of global warming. Carbon dioxide, along with other greenhouse gases, is one of the leading causes of our Earth's rise in temperature. This is because greenhouse gases trap the planet's heat inside its atmosphere, preventing it from leaving the Earth's surface. </span>

5 0

4 years ago

The molecule shown here can decolourise bromine water (above)

Sedaia [141]

Answer:

B hopefully this helps you

3 0

3 years ago

What is napping in the picture ​

What is napping in the picture