Ask question

Ask question

All categories

3 years ago

11

An elevator at a construction site has a maximum capacity of 3325 pounds. If the elevator operator weighs 225 pounds and each ce

ment bag weighs 75 pounds, how many bags of cement can be safely lifted on the elevator in one trip?

1 answer:

postnew [5]3 years ago

5 0

Answer: 41

3325 - 225 = 3,100
3,100 / 75 = 41.3 but you can’t take .3 bags so you round down to 41

You might be interested in

For what value of x is line a parallel to line b?<br><br> (Yo, please help me so I can go to sleep.)

iogann1982 [59]

X=20

If they're parallel the other number in the same spot as 5x+15 equals that, so 5x+15=115 because if they are parallel they're the same if same spot and same line going through them.

115-15 = 100
5x=100
Divide by 5 both sides
X=20

If x=20 then these lines would be parallel

6 0

3 years ago

Lebron wants to put a fence around a community garden plot. The plot is a rectangular shape with a length twice as long as its w

tatyana61 [14]

Answer:

60 feet of fencing

Step-by-step explanation:

Let x feet be the width of the garden plot, then 2x feet is the length of the garden plot.

The area of the garden plot is

$A=x\cdot 2x\\ \\200=2x^2\\ \\100=x^2\\ \\x=10\ feet\\ \\2x=20\ feet$

Find the perimeter of the rectangular garden plot:

$P=x+2x+x+2x\\ \\=10+20+10+20\\ \\=60\ feet$

5 0

3 years ago

Read 2 more answers

Four less than the sum of a number and 20 is 16. What is the number

Allushta [10]

[tex]4 - (x + 20 ) = 16

x=0

3 0

3 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago

The Walker family is selecting a furniture set. A furniture set has a bed, a desk, and a dresser. There are 2 beds, 2 desks, and

finlep [7]

Answer:

They can select total 8 different furniture sets.

Step-by-step explanation:

Here given

The different choice of beds = 2

The different choice of dresser = 2

The different choice of desks = 2

And they need to choose 1 bed, 1 desk , 1 dresser

So, choice available for a desk = 2

Similarly, choice available for dresser = 2

and choice available for bed = 2

HENCE, THE TOTAL CHOICE OF PERMUTATION IS = 2 x 2 x 2 = 8

So they can select their furniture set in 8 different ways.

7 0

3 years ago