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Doss [256]
3 years ago
14

How long does it take a 22 kW steam engine to do 5.6 × 107 J of work? Answer in units of s.

Physics
1 answer:
Lena [83]3 years ago
5 0
<h2>Time needed is 2545.45 seconds.</h2>

Explanation:

We know equation for power

               \texttt{Power = }\frac{\texttt{Work}}{\texttt{Time}}

Here we need to find time when for a 22 kW steam engine to do 5.6 × 10⁷ J of work.

So

        Work = 5.6 × 10⁷ J

        Power = 22 kW = 22 x 10³ W

Substituting

        \texttt{Power = }\frac{\texttt{Work}}{\texttt{Time}}\\\\22\times 10^3=\frac{5.6\times 10^7}{\texttt{Time}}\\\\\texttt{Time}=2545.45s

Time needed is 2545.45 seconds.

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How does inertia explain why it is difficult to stop a moving<br> skateboard?
My name is Ann [436]

Answer:

(Example Person) has to push hard to get the skateboard started, but once it begins moving, it takes much less effort to keep it rolling over the smooth, flat pavement. In fact, if (Example Person) tries to stop the rolling skateboard, it may take as much effort to stop it as it did to start it rolling in the first place.

Explanation:

Hope this helps :)

6 0
3 years ago
A person who studies physics is known as
Leto [7]
Physicists. Welcome :)
4 0
3 years ago
Read 2 more answers
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1.Landslide   2. Delta    3. Moving water    4. Erosion    5. Abrasion and Deflation

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7 0
4 years ago
An object has a mass of 6kg. calculate it's gpe​
m_a_m_a [10]

Explanation:

When m=<em>mass</em>

G=<em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>e</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>d</em><em>u</em><em>e</em><em> </em><em>t</em><em>o</em><em> </em><em>gravity</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>H</em><em>=</em><em>h</em><em>e</em><em>i</em><em>g</em><em>h</em><em>t</em>

<em>U</em><em>s</em><em>i</em><em>n</em><em>g</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em>

<em>M</em><em>g</em><em>h</em>

<em>(</em><em>M</em><em>=</em><em>6</em><em>, </em><em>g</em><em>=</em><em>10</em><em>,</em><em>h</em><em>=</em><em>?</em><em>) </em>

6×10×h

=60joules

7 0
3 years ago
How much tension must a rope withstand if used to accelerate a 960-kg car from rest horizontally along a frictionless surface to
Svetach [21]
Use a=(dv/dt)         (change in velocity/ change in time)=acceleration
(1.2/5)=acceleration

F=ma (Newton's second law, Force= Mass x Acceleration

=960 x 0.24     F=230.4N If  T<230.4N then the tow rope will hold

7 0
3 years ago
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