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Doss [256]
3 years ago
14

How long does it take a 22 kW steam engine to do 5.6 × 107 J of work? Answer in units of s.

Physics
1 answer:
Lena [83]3 years ago
5 0
<h2>Time needed is 2545.45 seconds.</h2>

Explanation:

We know equation for power

               \texttt{Power = }\frac{\texttt{Work}}{\texttt{Time}}

Here we need to find time when for a 22 kW steam engine to do 5.6 × 10⁷ J of work.

So

        Work = 5.6 × 10⁷ J

        Power = 22 kW = 22 x 10³ W

Substituting

        \texttt{Power = }\frac{\texttt{Work}}{\texttt{Time}}\\\\22\times 10^3=\frac{5.6\times 10^7}{\texttt{Time}}\\\\\texttt{Time}=2545.45s

Time needed is 2545.45 seconds.

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According to Newton's 2nd Law of Motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is
Mkey [24]

According to Newton's second Law of motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is 1m/s².

<h3>How to calculate acceleration?</h3>

The acceleration of a moving body can be calculated by dividing the force of the body by its mass.

According to this question, the mass of an object is 10 kg and the force is 10 newtons, then the acceleration can be calculated as follows:

acceleration = 10N ÷ 10kg

acceleration = 1m/s²

Therefore, according to Newton's second Law of motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is 1m/s².

Learn more about acceleration at: brainly.com/question/12550364

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8 0
2 years ago
Rope BCA passes through a pulley at point C and supports a crate at point A. Rope segment CD supports the pulley and is attached
RUDIKE [14]

Answer:

Wmax = 63.65 ≈ 64 lb

Explanation:

6 0
3 years ago
A long solenoid that has 1 200 turns uniformly distributed over a length of 0.420 m produces a magnetic field of magnitude 1.00
Fantom [35]

Answer:

<h2>The current required  winding is  2.65*10^-^2 mA</h2>

Explanation:

We can use the expression B=μ₀*n*I-------1 for the magnetic field that enters a coil  and

n= N/L (number of turns per unit length)

Given data

The number of turns n= 1200 turns

length L= 0.42 m

magnetic field B= 1*10^-4 T

μ₀= 4\pi*10^-^7 T.m/A

Applying the equation  B=μ₀*n*I

I= B/μ₀*n

I= B*L/μ₀*n

I= \frac{1*10^-^4*0.42}{4\pi*10^-^7*1.2*10^3 }

I= 2.65*10^-^2 mA

8 0
3 years ago
Rebecca is 24 years old and is involved in a bad automobile accident. Under her current automobile insurance, she chose a 2,000
olga nikolaevna [1]
This is true.  Not sure what you're looking for as an answer.  But this would be true, you have to pay the deductible before a company will pay.  EXCEPT in the case that it's not your fault and the other driver is paying. 
5 0
3 years ago
17) The charge of an anti-charm quark isapproximately equal to
Gnom [1K]

The charge of an anti-charm quark is approximately equal to  +5.33 ×10⁻²⁰ C.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

The charge on electron is equal to e = -1.6 x 10⁻¹⁹C

The charge of an anti- charm quark is +23 times the magnitude of charge on electron.

So, charge on  anti- charm quark is

q = +1/3 x ( 1.6 x 10⁻¹⁹C)

q =  +5.33 ×10⁻²⁰ C

Thus, the charge of an anti-charm quark is approximately equal to +5.33 ×10⁻²⁰ C.

Learn more about electrons.

brainly.com/question/1255220

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7 0
2 years ago
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