Question is incomplete. Missing part:
Find the charge on the capacitor at the following times:
1) t = 0 mu S
2) t = 1 mu S
3) t = 50 mu S
1) 
We start by calculating the initial charge on the capacitor. For this, we can use the following relationship:

where
C is the capacitance
Q0 is the initial charge stored
V0 is the initial potential difference across the capacitor
When the capacitor is connected to the battery, we have:


Solving for
,

So, when the battery is disconnected, this is the charge on the capacitor at time t = 0.
2) 
To find the charge on the capacitor at any other time t, we use the equation:

where

t is the time
is the resistance
is the capacitance
Therefore, at time
, we have:

3) 
As before, we use again the equation:

However, here the time to consider is

Substituting into the formula,
