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serg [7]
3 years ago
11

A certain fluid (with properties listed below) is heated from 25 to 75 °C as it moves at 0.2 m/s through a straight thin-walled

tube of 12.7-mm diameter. The tube is 10 m long and provides a uniform heat flux. The fluid enters the tube with a fully developed velocity profile and a uniform temperature profile.
a) What is the required heat flux?
b) What is the thermal entrance length?
c) What is the surface temperature of the tube at the exit (x-3 m)?
d) What is the surface temperature of the tube at a distance of 0.5 m from the entrance?
Physics
1 answer:
dexar [7]3 years ago
3 0

Answer:

not sure. I'll try answering this later

Explanation:

I'm not sure. I'll try answering this later .

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Four springs with the following spring constants, 113.0 N/m, 65.0 N/m, 102.0 N/m, and 101.0 N/m are connected in series. What is
Llana [10]

Answer:

K_e_q=22.75878093\frac{N}{m}

f=1.363684118Hz

Explanation:

In order to calculate the equivalent spring constant we need to use the next formula:

\frac{1}{K_e_q} =\frac{1}{K_1} +\frac{1}{K_2} +\frac{1}{K_3} +\frac{1}{K_4}

Replacing the data provided:

\frac{1}{K_e_q} =\frac{1}{113} +\frac{1}{65} +\frac{1}{102} +\frac{1}{101}

K_e_q=22.75878093\frac{N}{m}

Finally, to calculate the frequency of oscillation we use this:

f=\frac{1}{2(pi)} \sqrt{\frac{k}{m} }

Replacing m and k:

f=\frac{1}{2(pi)} \sqrt{\frac{22.75878093}{0.31} } =1.363684118Hz

4 0
3 years ago
Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that ha
jasenka [17]

Explanation:

It is given that,

Mass of an object, m=4\times 10^5\ kg

(a) Time period of oscillation, T = 2.4 s

The formula for the time period of spring is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

Where

k is the force constant

k=\dfrac{4\pi ^2 m}{T^2}

k=\dfrac{4\pi ^2 \times 4\times 10^5}{(2.4)^2}

k=2.74\times 10^6\ N/m

(b) Displacement in the spring, x = 2.2 m

Energy stored in the spring is given by :

U=\dfrac{1}{2}kx^2

U=\dfrac{1}{2}\times 2.74\times 10^6\ N/m\times (2.2\ m)^2

U=6.63\times 10^6\ J

Hence, this is the required solution.

7 0
4 years ago
3 rights for all U.S residents
mezya [45]
<span> The right to form a militia and to keep and bear arms.
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Powers not given to the federal government by the Constitution belong to the states or the people.</span><span>


Freedom of religion, freedom of speech and the press, the right to assemble, the right to petition government.
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4 0
3 years ago
A pitcher releases a fastball that moves toward home plate.
Vsevolod [243]

The two additional forces that act on the ball as it travels between the pitcher and the home plate are air resistance and gravity.

<h3>What are the forces that affect object in motion;</h3>
  • Air resistance: this is the force that oppose the motion of an object in air due to frictional force
  • Gravity: this is the force due to weight of the object and acts downwards.

The two additional forces that act on the ball as it travels between the pitcher and the home plate include:

  1. Air resistance and
  2. Gravitational force  

<h3>How the forces affect the motion of the ball</h3>
  • Air resistance oppose the motion of the ball as it travels in air.
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Learn more about forces on object in motion here: brainly.com/question/10454047

5 0
2 years ago
The uniform circular motion of a space station can be used to create artificial gravity. This can be done by adjusting the angul
DENIUS [597]

Answer:

The acceleration at the astronaut's head decreases.

Explanation:

Since the centripetal acceleration equals acceleration due to gravity,

a = g = GM/R². since a changes infinitesimally from his foot to his head, we differentiate a with respect to r to get da/dr = -2GM/R³.

So, da, the change in acceleration = -2GMdR/R³ = -2gdR/R = -2 × 9.8/6.4 × 10⁶ m =  -3.0625 × 10⁻⁶dR m/s².

Since dR = height of astronaut = 1.80 m, da = -3.0625 × 10⁻⁶ × 1.8 = -5.5125 × 10⁻⁶ m/s².

So the acceleration at the astronaut's head is g + da = 9.8 - 0.0000055125 = 9.7999944875 m/s².

So the acceleration at the astronaut's head decreases.

3 0
3 years ago
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