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nordsb [41]
3 years ago
6

A 20.0-kg mass is traveling to the right with a speed of 3.00 m/s on a smooth horizontal surface when it collides with and stick

s to a second 20.0-kg mass that is initially at rest but is attached to a light spring with force constant 170 N/m . Find the frequency of the subsequent oscillations.
Express your answer with the appropriate units. Find the amplitude of the subsequent oscillations.

Express your answer with the appropriate units.
Physics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

a) 0.328 Hz b) 73 cm (0.73 m)

Explanation:

Using law of conservation of momentum:

M1U1 + M2U2 = V(M1+M2) since the mass stuck together. where M1 is the mass 20 kg travelling with the U1  speed 3m/s and M2 is the 20kg at rest with U2 = 0 and V is the final speed of the mass after collision.

substitute the values into the equation

20 × 3 + 20 ×0 = V (20+20)

V = 60 / 40 = 1.5 m/s

The period of the oscillation can be calculated with the formula:

T = 2π√ ( m/k)  where T is the period in seconds and F is the frequency of the oscillation

substitute the values into the formula

T = 2×3.142×√ (40/170) = 3.05s

T = 1/F

F = 1/T = 1/ 3.05 = 0.328Hz

b) The amplitude of the oscillation can calculated using the formula

V = x√(K/m) where x is the amplitude in cm and V is the maximum speed that caused the displacement (amplitude) x

substitute the values into the formula

1.5 = x × √ (170/40) = x × 2.062

divide both side by 2.062

x = 1.5 / 2.062 = 0.73m = 0.73 cm

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The halter add the distance to the jump in meters is 0.55 m.

<h3>What is projectile?</h3>

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.

The magnitude of velocity u =10.3 m/s, angle of jumping θ = 22.8 degrees.

Components of velocity in x and y direction are

Vx = 10.3 cos 22.8 = 9.5 m/s

Vy = 10.3 sin 22.8 = 4 m/s

Maximum Range of athlete achieved using halter is given by

R = u²sin2θ /g

where, u = initial velocity, θ is the angle of projection and g is the gravitational acceleration.

Substituting the values, we get

R = (10.3)² sin(2 x 22.8 °) / 2 x 9.81

R = 7.75m

At the peak of jump you throw two 5.5 kg masses horizontally behind you such that their velocity is zero in the ground's reference frame.

The momentum is conserved in this situation,

(M+2m)Vxo =MVx'

Vx' = (M+2m)/M x Vxo'

Change in x component of velocity ΔVx = Vx' -Vxo

Vxo = 2m/M x Vx

Vxo = 2 x 5.5 /78 x 9.5

Vxo = 1.34 s

Maximum height gained when final velocity is zero

Vy = 0 = Vyo -gt

time t = Vyo/g = 4/9.8 = 0.41s'

Increase in range by using of halters is

ΔR = ΔVx' x t

ΔR = 1.34 x 0.41

ΔR =0.55m

Thus, the halter add the distance to the jump in meters is 0.55 m.

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How do rocks within Earth change as P waves pass? How do rocks within Earth change as P waves pass? Rocks within Earth both expa
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Rocks within Earth both expand and contract as P waves pass

Explanation:

Rocks within the earth both expands and contracts as P-waves passes through them. P-waves are elastic waves.

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A camcorder has a power rating of 15 watts. If the output voltage from its battery is 5 volts, what current does it use?
MrMuchimi

Formula

W = E * I

Givens

E = 5 volts

W = 15 watts

I = ?

Solution

W = E * I

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