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Mila [183]
3 years ago
7

Help!

Physics
1 answer:
Artemon [7]3 years ago
5 0

Answer:

5 m/s² & 20 m

Explanation:

#1

Acceleration = Final velocity - Initial velocity/Time

Acceleration = 15 - 5/2

Acceleration = 10/2

Acceleration = 5 m/s²

#2

v² - u² = 2as

(15)² - (5)² = 2(5)(s)

225 - 25 = 10s

200 = 10s

200/10 = s

20 = s

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3 years ago
What was birta system​
Amanda [17]

Answer:

The act of distributing land to an individual as salary, donation, present or reward is called birta. There was the Birta system during the Malla, Shah and Rana rule in the country.

Explanation:

Act: (a) "Birta land" means any kind of land obtained or possessed in such a way that the land is wholly exempt from the State Land Tax, or that the tax payable thereon is less than the tax imposed on Raikar land of similar type in the same place, and this term also includes any land as defined in Clauses

6 0
3 years ago
At a distance of 8 m, the sound intensity of one speaker is 66 dB. If we were to place 3 speakers in a circle of radius 8 m, wha
ludmilkaskok [199]

Answer:

dβ = 70. 77 dβ

Explanation:

The intensity of sound in decibels is

         dβ = 10 log I/I₀

let's look for the intensity of this signal

         I / I₀ = 10 dβ/10

         I / I₀ = 3.981 10⁶

the threshold intensity of sound for humans is I₀ = 1 10⁻¹² W / m²

         I = 3.981 10 ⁶ 1 10⁻¹²

         I = 3,981 10⁻⁶ W / m²

It is indicated that 3 cornets are placed in the circle, for which total intensity is

        I_total - 3 I

        I_total = 3  3,981 10⁻⁶

        I_total = 11,943 10⁻⁶ W / m²

let's reduce to decibels

      dβ = 10 log (11,943 10⁻⁶/1 10⁻¹²)

      dβ = 10  7.077

      dβ = 70. 77 dβ

3 0
3 years ago
According to Newton's second law of motion what is force equal to
lubasha [3.4K]
Newton's second law of motion<span> can be formally stated as follows: The acceleration of an object as produced by a net </span>force<span> is directly proportional to the magnitude of the net </span>force, in the same direction as the netforce<span>, and inversely proportional to the mass of the object</span>
8 0
3 years ago
Read 2 more answers
A thin, circular hoop with a radius of 0.22 m is hanging from its rim on a nail. When pulled to the side and released, the hoop
Alex73 [517]

Answer:

Period of oscillation = 1.33 seconds

Explanation:

The period of oscillation is given by:

T = 2π√[I/(MgL)] 

for I = 2MR² and L = R,

Given: L = 0.22m = R

T = 2π√[2R/g] 

T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]

T = 6.284 Sqrt(0.44/9.8)

T = 6.284 Sqrt(0.0449)

T = 6.284 × 0.2119

T = 1.33 sec

6 0
4 years ago
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