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mina [271]
3 years ago
5

imagine que você se encontra parado à frente de um espelho plano, que também se encontra em repouso. imagine agora que esse espe

lho passe a se deslocar com uma velocidade constante e igual a 10 m/s. neste caso a velocidade da imagem formada, em relação a você, que é o objeto fixo da situação, será igual a:
Physics
1 answer:
atroni [7]3 years ago
4 0

Answer:

The speed of the image is changing with the same 10 m/s speed, in the direction of the mirror's motion.

Explanation:

For a flat mirror, it is known that the object distance is always equal to the image distance, this is proven from the mirror equation

(1/f) = (1/u) + (1/v)

f = focal length = ∞ (for a flat mirror, the focal length is theoretically imfinity)

v = image distance from the mirror

u = object distance from the mirror

For a flat mirror, (1/f) = (1/∞) = 0

0 = (1/u) + (1/v)

(1/v) = -(1/u)

v = -u

The minus sign means that the image distance is measured in the opposite direction to the object distance.

(dv/dt) = -(du/dt)

So, if the mirror starts moving at a particular speed, as long as the object doesn't move, the object's distance from the mirror is changing according to the speed of the mirror alas in the direction opposite the mirror's motion.

Hence, if (du/dt) = -10 m/s

(dv/dt) = 10 m/s

Meaning that the speed of the image is changing with the same 10 m/s speed, in the direction of the mirror's motion.

Hope this Helps!!!

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A spring on Earth has a 0.500 kg mass suspended from one end and the mass is displaced by 0.3 m. What will the displacement of t
julia-pushkina [17]

To solve this problem we will apply the concepts related to the Force of gravity given by Newton's second law (which defines the weight of an object) and at the same time we will apply the Hooke relation that talks about the strength of a body in a system with spring.

The extension of the spring due to the weight of the object on Earth is 0.3m, then

F_k = F_{W,E}

kx_1 = mg

The extension of the spring due to the weight of the object on Moon is a value of x_2, then

kx_2 = mg_m

Recall that gravity on the moon is a sixth of Earth's gravity.

kx_2 = m\frac{g}{6}

kx_2 = \frac{1}{6} mg

kx_2 = \frac{1}{6} kx_1

x_2 = \frac{1}{6} x_1

We have that the displacement at the earth was x_1 = 0.3m, then

x_2 = \frac{1}{6} 0.3

x_2 = 0.05m

Therefore the displacement of the mass on the spring on Moon is 0.05m

6 0
3 years ago
I NEED THIS FAST
Novay_Z [31]
I think it is b , that what I would i pick
7 0
3 years ago
A negative test charge experiences a force to the right as a result of an electric field. Which is the best conclusion to draw
Alona [7]

Answer:a

Explanation:

4 0
3 years ago
What are the properties of sound waves and how do they affect the sound?
Marina86 [1]
The more sound waves a sound produces, the higher the pitch. Meaning if a sound has a high frequency, it will produce a high-pitched, shrill sound, while sounds with a lower frequency produce lower, deeper sounds, like bass sounds. ( i hope this helps)
6 0
1 year ago
a conducting rod whose length is 25 cm is placed on a u-shaped metal wire that has a resistance of 8.0 ω . the wire and the rod
andreyandreev [35.5K]

Answer:

The current is I  =  1 A

The direction is anti-clockwise

Explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

     the length of the conducting rod is L  = 25 \ cm =  \frac{25}{100}  =  2.5 \ m

     The resistance is  R = 8  \Omega

      The magnetic field is  B = 0.40\ T

        The speed of the rod is v = 6.0 m/s

The emf induced is

          \epsilon  = BLv

 substituting values we have

           \epsilon = 0.40 * 2.5 * 8

           \epsilon = 8V

From ohm law the induced current would be

      I  =  \frac{\epsilon}{R }

 substituting values we have

       I  =  \frac{8}{8 }      

       I  =  1 A

The direction anticlockwise this because according to lenze law the current due to change in magnetic field will act in the opposite direction of the  force causing the magnetic field to change

4 0
3 years ago
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