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3 years ago

action and reaction are equal in magnitude and opposite direction then why they don't balance each other

1 answer:

8 0

Action and reaction are equal in magnitude and opposite direction by they don't balance each other because they don't occur on the same body. Action is involved on one body and reaction is involved on another body.
Hope you understood...

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The scientific method _____.

Lubov Fominskaja [6]

The answer is D I took the test

3 0

3 years ago

A man does 500 j work pushing a car a distance of 2m how much force does he apply

olasank [31]

Answer: 250 N

Explanation:

Use equation for work

W=F*d

d=2m

W=500J

F=?

-----------------------

W=Fd

F=W/d

F=500J/2m

F=250N

6 0

3 years ago

Read 2 more answers

A 1.0-m-diameter vat of liquid is 2.0 m deep. The pressure at the bottom of the vat is 1.3 atm. What is the mass of the liquid i

gladu [14]

Answer:

The mass of the liquid = 10538 kg

Explanation:

The pressure in a liquid is

P = ρgh ......................... Equation 1

ρ = P/gh ...................... Equation 2

Where P = pressure, ρ = density, g = acceleration due to gravity, h = height.

Given: p = 1.3 atm, h = 2.0 m, g = 9.81 m/s²

If, 1 atm = 1.013×10⁵ N/m²

Then, P = 1.3×1.013×10⁵ N/m² = 1.3169×10⁵ N/m²

Substituting in equation 2,

ρ = 1.3169×10⁵/(9.81×2)

ρ = 1.3169×10⁵/19.62

ρ = 6712.03 kg/m³.

But Density,

ρ = m/v

m = ρ × v........................ Equation 3

Where m = mass of the liquid, v = volume of the liquid in the vat

v = πd²h/4, where d = diameter = 1.0 m, h = 2.0 m.

v = 3.14(1)²×2/4

v = 1.57 m³ also, ρ = 6712.03 kg/m³.

Substituting into equation 3

m = 1.57×6712.03

m = 10537.887 kg

m ≈ 10538 kg.

Thus the mass of the liquid = 10538 kg

3 0

3 years ago

PLEASE HELP !! A 10 ohm resistor is connected to a 9V battery how much current is flowing through the circuit?

kompoz [17]

Resitance (R)= 10 Ohm

Potential difference (V) = 9V

V= IR

I= V/R

I= 9/10

I= 0.9 Ampere

Therefore 0.9 Ampere of current is flowing through the circuit.

8 0

3 years ago

Consider an object with weight on the Earth W_earth. The gravity of the Earth is g. If it is moved to another planet with gravit

Mazyrski [523]

Answer:

$W_{Planet} = \frac{W_{Earth}}{g}\times a$

Explanation:

We know that weight of an object on Earth is,

$W_{Earth} = m\times g$

Thus,

$m = \frac{W_{Earth}}{g}$

where,

m = mass of an object, which is constant and is independent of gravity

g = acceleration due to gravity on Earth

On the new planet, gravity = a

Thus the weight of the object on the new planet will be

$W_{Planet} = m\times a$

$W_{Planet} = \frac{W_{Earth}}{g}\times a$

5 0

3 years ago