Answer:
10 30
15 45
so the third one
Step-by-step explanation:
It being multiplied by 3
2x3=6
3x3=9
10x3=30
15x3=45
(x^1/8 y^1/4 z^1/2)^8
(8 √x 4 √y √z^8)
(8 √x 8 √y^2 8 √z^4)^8
8 √xy^2z^4^8
Solution: xy^2 z^4
Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
The answer is C. All calculations of a cone or the cone equal up to 353.77. Hope this helps!
