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Oduvanchick [21]

4 years ago

8

The neutron was not discovered until 1932, more than thre

1 answer:

Llana [10]4 years ago

7 0

Answer:

<em>Correct option is D) The neutron has a neutral charge, which made it impossible to discover using previous experiments with positive and negative charges.</em>

Explanation:

The protons are the positively charged particles of an atom. The electrons are the negatively charged particles of an atom. As both the particles carry some kind of charge i.e either positive or negative, hence their discovery was easier.

The neutrons are the part of an atom which are neutral and do not carry any charge. Hence, their discovery took a more longer time as compared to the discovery of electrons and protons.

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HELP! <br> A. W<br> B. X<br> C. Y<br> D. Z

tamaranim1 [39]

Answer:

B

Explanation:

7 0

3 years ago

Calculate the molar solubility of lead thiocyanate in pure water. The molar solubility is the maximum amount of lead thiocyanate

OLga [1]

Answer:

$Molar solubility(S)=1.71\times10^{-2} mole/litre$

Explanation:

Assume Ksp of $Pb(SCN)_{2}$ = $2\times10^{-5}$ ( it is general value ,i took it because not given in question)

molar solubilty means how much maximum mole of lead thiocynate is dissolved in one litre of solvent.

Ksp=solubility product;

$Pb(SCN)_2= Pb^{2+} +2SCN^-$

Lets molar solubilty of $Pb(SCN)_2$ is S then

$[Pb^{+2}]=S;$

$[SCN^{-1} ]=2S;$

$Ksp =S\times(2S)^{2} =2\times10^{-5}$

$4S^{3}=2\times10^{-5}$

$S=1.71\times10^{-2} mole/litre$

4 0

3 years ago

Cuántos gramos de cloruro de magnesio se pueden obtener si se hacen reaccionar 354,9g de cloruro de titanio (IV) y 285g de magne

DENIUS [597]

Answer:

sorry I dont speak Spanish

8 0

3 years ago

How many moles of iron chloride are produced when 6 moles of chlorine gas react with excess iron

kherson [118]

Answer:

12.0107

Explanation:

Hope this helps!

6 0

4 years ago

Calculate the pH of the solution formed when 45.0 mL of 0.100M NaOH solution is added to 50.0 mL of 0.100M CH3COOH (Ka for aceti

pav-90 [236]

Answer:

pH of soltion will be 5.69

Explanation:

The pH of the solution will be due to excessive acid left and the salt formed. Thus, it will form a buffer solution.

The pH of buffer solution is calculated from Henderson Hassalbalch's equation, which is:

$pH=pKa+log(\frac{[salt]}{[acid]} )$

$pKa=-log(Ka)$

$pKa=-log(1.8X10^{-5})=4.74$

The moles of acid taken :

$moles=molarityXvolume=0.1X50=5mmol$

The moles of base taken:

$moles=molarityXvolume=0.1X45=4.5mmol$

The moles of acid left after reaction :

$5-4.5=05mmol$

The moles of salt formed = 4.5mmol

Putting values in equation

$pH=pKa+log(\frac{[salt]}{[acid]} )=4.74+log(\frac{4.5}{0.5})=5.69$

8 0

3 years ago