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user100 [1]
3 years ago
15

The charges and sizes of the ions in an ionic compound affect the strength of the electrostatic attraction holding that compound

together. Based on ion charges and relative ion sizes, rank these ionic compounds by their expected melting points from highest to lowest
a.SrCl2 ,b.CsBr ,c.RbCl ,d.SrS
Chemistry
1 answer:
qwelly [4]3 years ago
4 0

Answer:

Decreasing order of melting point:

SrS > SrCl_2 > RbCl > CsBr

Explanation:

Born–Landé equation explained the relation between lattice energy, charges and sizes of ions present in a compound.

U=-k\frac{Q_1Q_2}{r_0}

Here, U is internal energy, Q_1\ and\ Q_2 are charges and r_0 is the size.

More the lattice energy more will be the energy to break ionic lattice in order to melt.

Therefore, more the lattice energy, more will be melting point.

Moreover, lattice energy is proportional to charge and inversely proportional to size.

Consider the compounds given

In SrCl_2,\ charges\ are\ Sr^{2+},\ Cl^-

In CsBr, charges are Cs^+,\ Br^-

In RbCl charges are Rb^+,\ Cl^-

In Srs, charges on ions are Sr^{2+},\ S^{2-}

Order of the sizes are as follows:

Cs > Rb

Br > Cl

Cs > Sr

Therefore, decreasing order of melting point:

SrS > SrCl_2 > RbCl > CsBr

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3 years ago
A fuel tank holds 22.3 gallons of gasoline. If the density is 0.8206 g/mL, what is the mass in kilograms of gasoline in a full t
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Answer:

m=69.3kg

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

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m=0.8206g/L*84.415L\\\\m=69.3kg

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Name the fundamental unit involved in the derived unit joule?​
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What sort of adaptations are usually passed on to the offspring of an organism
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4 years ago
A student sets up the following equation to convert a measurement. The (?) Stands for a number the student is going to calculate
Vika [28.1K]

Answer:

\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 3.0 \times 10^{-7} \text{ m}^{3}  

Explanation:

0.030 cm³ × ? = x m³

You want to convert cubic centimetres to cubic metres, so you multiply the cubic centimetres by a conversion factor.

For example, you know that centi means "× 10⁻²", so  

1 cm = 10⁻² m

If we divide each side by 1 cm, we get 1 = (10⁻² m/1 cm).

If we divide each side by 10⁻² m, we get (1 cm/10⁻² m) = 1.

So, we can use either (10⁻² m/1 cm) or (1 cm/10⁻² m) as a conversion factor, because each fraction equals one.

We choose the former because it has the desired units on top.

The "cm" is cubed, so we must cube the conversion factor.

The calculation becomes

\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 0.30 \times 10^{-6}\text{ m}^{3} = \mathbf{3.0 \times 10^{-7}} \textbf{ m}^{\mathbf{3}}\\\\\textbf{0.30 cm}^{\mathbf{3}} \times \left (\dfrac{\mathbf{10^{-2}}\textbf{ m}}{\textbf{1 cm}}\right )^{\mathbf{3}} = \mathbf{3.0 \times 10^{-7}} \textbf{ m}^{\mathbf{3}}

7 0
3 years ago
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