Answer:
Measure the volume of water poured into a graduated cylinder, then place the object in the water and remeasure the volume. The difference between the two volume measurements is the volume of the object. Now simply divide the mass by the volume to calculate the density of the object.
<h3>
Answer:</h3>
43.5 mL
<h3>
Explanation:</h3>
We are given;
- Molarity of dilute acetic acid is 1.74 M
- Volume of the solution that needs to be prepared is 200 mL
- Molarity of the stock solution 8 M
We are required to determine the volume of acid that must be used.
- We need to know the dilution formula;
- According to the dilution equation;
M1V1 = M2V2
Rearranging the formula;
V1 = M2V2 ÷ M1
= (1.74 M × 200 mL) ÷ 8 M
= 43.5 mL
Therefore, the volume of the concentrated acid that must be added is 43.5 mL
Answer:
a) solubility increases
b) solubility decreases
c) solubility increases
Explanation:
I) Fe^3+(aq) + 3Br^- --------> FeBr3 (aq) solubility increases
II) Fe^3+(aq) + 3OH^- ---------> Fe(OH)3(s) solubility decreases
III) Fe^3+(aq) + 6CN^- -----------> [Fe(CN)6]^3- (aq) solubility increases
The ionic equations shown above shows the possible changes in solubility when Fe(OH)3 is added to each of the solutions mentioned in the question.
