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Bumek [7]
2 years ago
14

You find out

Chemistry
1 answer:
Temka [501]2 years ago
6 0

Answer: 62.173%

explanation:

equation for percentage mass of an element in a compound = (Mass of element in compound / mass of the whole compound ) × 100%

% mass = (46.63÷75.00) × 100

= 0.62173 × 100

= 62.173%

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c

Explanation:

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Which list ranks the gasses in the correct order from the
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Answer:

D. chlorine, oxygen, nitrogen, hydrogen.

Explanation:

  • Thomas Graham found that, at a constant  temperature and pressure the rates of effusion  of various gases are inversely proportional to  the square root of their masses.

<em>ν ∝ 1/√M</em>

where ν is the rate of effusion and M is the atomic  or molecular mass of the gas particles.

  • The molecular mass for the listed gases are:

O₂: 32.0 g/mol,

Cl₂: 70.906 g/mol,

N₂: 28.0 g/mol,

H₂: 2.0 g/mol.

  • Hence, the smallest molecular mass of the gas, the fastest rate of effusion.

So, the order from the slowest to the fastest rate of effusion is:

<em>Chlorine, oxygen, nitrogen, hydrogen.</em>

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8 0
2 years ago
An aqueous solution of Calcium Chloride reacts with an aqueous solution
Tems11 [23]

Answer:

the products formed are : -

1. CaCO3 - Calcium Carbonate

2. NaCl - Sodium Chloride

Explanation:

Calcium chloride reacts with Sodium carbonate to form Calcium carbonate and Sodium chloride. this reaction is a double displacement reaction.

here's the balanced chemical equation for the above reaction : -

CaCl2 + Na2CO3 =》CaCO3 + 2 NaCl

7 0
3 years ago
What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

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Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

8 0
3 years ago
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