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jeka94
3 years ago
8

Which of the following is a basic equation?

Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

<h2>A. b + 3 = 5</h2>

 \tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}

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A manufacturer is planning to sell a new product at the price of 210 dollars per unit and estimates that if x thousand dollars i
sattari [20]

Answer:

Development costs: $2757

Promotion costs: $3155

Step-by-step explanation:

This might seem like a two-variable problem, but in actuality it's not - because the demand function is a sum of two components, each being independent and using only one variable, we can solve for the two separately.

Moreover, the price per unit and cost per unit is constant, so each product yields exactly $80 ($210 - $130).

Let's solve separately.

We need to maximize:

$80 * 160y/(y+4) - 1000y = $12800 * y/(y+4) - $1000*y

$80 * 170x/(x+7) - 1000x = $13600 * x/(x+7) - $1000*x

Let's go:

$12800 * y/(y+4) - $1000*y = $12800 * (1 - 4/(y+4)) - $1000y = $12800 - $51200/(y+4) - $1000*y

we analyze the derivative. $12800 is a constant, so we can skip it. Derivative of 1/(y+4) is -(y+4)^-2, derivative of $1000y is $1000.

deriv = $51200/(y+4)/(y+4) - $1000

We find the changepoints by analyzing $51200/(y+4)/(y+4) - $1000 = $0. We don't need to worry about y+4 = 0 because we cannot spend negative money on development/advertisement.

(y+4)^2 = $51.2

y+4 ~= 7.155417528 (or -y-4 = 7.1554... but it doesn't make sense because negative budget so we don't analyze).

y ~= 3.155417528

lastly, we should check that it's actually a maximum there - but it is, the original function goes to negative infinity.

rounding $1000y to the nearest dollar gives us $3155

Let's do the same for x:

$13600 * x/(x+7) - $1000*x = $13600 * (1 - 7/(x+7)) - $1000x = $13600 - $95200/(x+7) - $1000*x

deriv = $95200/(x+7)/(x+7) - $1000

$95200/(x+7)/(x+7) - $1000 = $0

(x+7)^2 = 95.2

(x+7) ~= 9.75704873412

x ~= 2.75704...

rounding $1000x to the nearest dollar yields $2757

3 0
3 years ago
What is the 7th term in the sequence below?
enot [183]

Answer:

C

my answer is the image above

5 0
3 years ago
Y=2x+3 <br> y=3x+1 <br> solve the system of equations using substitution
Lynna [10]

Answer:

(2, 7 )

Step-by-step explanation:

Given the 2 equations

y = 2x + 3 → (1)

y = 3x + 1 → (2)

Substitute y = 3x + 1 into (1)

3x + 1 = 2x + 3 ( subtract 2x from both sides )

x + 1 = 3 ( subtract 1 from both sides )

x = 2

Substitute x = 2 into either of the 2 equations for corresponding value of y

Substituting x = 2 into (1)

y = 2(2) + 3 = 4 + 3 = 7

Solution is (2, 7 )

4 0
3 years ago
Read 2 more answers
Find the number n that fits all of the conditions
finlep [7]
Your answer would be 12
7 0
3 years ago
An electronics firm claims that the proportion of defective units of a certain process is 5%. A buyer has a standard procedure o
lesya692 [45]

Answer:

0.0006 = 0.06% probability of this occurrence

Step-by-step explanation:

For each unit, there are only two possible outcomes. Either it is defective, or it is not. The probability of an unit being defective is independent of any other unit, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

An electronics firm claims that the proportion of defective units of a certain process is 5%.

This means that p = 0.05

A buyer has a standard procedure of inspecting 15 units selected randomly from a large lot.

This means that n = 15

a) What is the probability of this occurrence?

Probability of 5 defective items, whch is P(X = 5). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{15,5}.(0.05)^{5}.(0.95)^{10} = 0.0006

0.0006 = 0.06% probability of this occurrence

8 0
3 years ago
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