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3 years ago

Solve this problem show work. -5/6 + 1/3

1 answer:

5 0

1/3 is the same as 2/6, so we can rewrite this as:

-5/6 + 1/3 = -5/6 + 2/6

To add fractions, add the numerators:

-5 + 2 = -3

So, -5/6 + 2/6 = -3/6

This can reduce, since 3 and 6 are divisible by 3.

-3/6 = -1/2

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Line EF has an equation of a line y = -2x + 7, and line GH has an equation of a line y = x -1. These two lines are

Dmitry_Shevchenko [17]

Intersecting but not at a right angle

7 0

3 years ago

How do you ordered pair that represents a solutions to the system of linear inequalities below?

ELEN [110]

Answer:

x=No (Minimum)

Step-by-step explanation:

Hope this helps

4 0

3 years ago

What is the answer to 7 or 8???

Eddi Din [679]

Answer:

7. parallel: k = 3

perpendicular: k = -4/3

8. $1300

Step-by-step explanation:

Rewrite each equation as the slope-intercept form of a linear equation:

y = mx + b (where m is the slope and b is the y-intercept)

8y = 12x + 6

⇒ $y=\dfrac32x+\dfrac34$

4y = k(2x + 10)

⇒ 4y = 2kx + 10k

⇒ $y = \dfrac12kx + \dfrac52k$

If the graphs are parallel their slopes will be the same.

$\implies \dfrac32=\dfrac12k$

$\implies k=3$

If the graphs are perpendicular then the product of their slopes will be -1.

$\implies \dfrac32 \times \dfrac12k=-1$

$\implies \dfrac12k=-\dfrac23$

$\implies k=-\dfrac43$

8. Create a linear equation, where x is the number of coffee mugs and y is the total cost (in dollars).

Choose 2 ordered pairs from the table: (10, 110) and (20, 195)

Let $(x_1,y_1)$ = (10, 110)

Let $(x_2,y_2)$ = (20, 195)

Use the slope formula to find the slope m:

$\implies m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{195-110}{20-10}=\dfrac{17}{2}$

Now use the point-slope form of linear equation:

$\implies y-y_1=m(x-x_1)$

$\implies y-110=\dfrac{17}{2}(x-10)$

$\implies y=\dfrac{17}{2}x+25$

Substitute x = 150 into the equation and solve for y:

$\implies y=\dfrac{17}{2}(150)+25=1300$

Therefore, the total cost of ordereing 150 mugs is $1300

5 0

2 years ago

Which of the following is the equation of a line perpendicular to the line y=-10×+1 passing through the point (5,7)

Juliette [100K]

Y = -10x + 1...slope here is -10. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal of a number, flip the number and change the sign. So our perpendicular line will need a slope of 1/10.

y = mx + b
slope(m) = 1/10
(5,7)....x = 5 and y = 7
now sub and find b, the y int
7 = 1/10(5) + b
7 = 1/2 + b
7 - 1/2 = b
14/2 - 1/2 = b
13/2 = b

so ur perpendicular line going thru (5,7) is y = 1/10x + 13/2

3 0

4 years ago

At the end of January of last year, stock A was selling at A dollars a share, and stock B was selling a B dollars a share, where

Maslowich

Answer: a) yNA/100

b) NA(y-x)/100

c) (NA)/B

Step-by-step explanation:

a) The total amount of dollars owned by the shares' owner = N number of shares × A dollars per share = NA dollars

This total is then transferred to buy B shares which then appreciates by y%.

The amount of increase in portfolio from January to June = y% of total dollars invested = y% of NA dollars = yNA/100

b) If the shares were left with A, the increase in portfolio from January to June would be x% and = x% of the total Dollar amount = x% of NA dollars = xNA/100

How much more money made in that time would be the difference in interest, between taking the dollars to invest in share B or keeping the dollars on investment A

That is, (yNA/100) - (xNA/100) = NA(y-x)/100

c) Total dollars available after sale of the A stock = NA

Number of B stock this dollar can buy = Total dollars available/amount of B stock per share

That is, (NA)/B

QED!

3 0

3 years ago

Solve this problem show work. -5/6 + 1/3​

Solve this problem show work. -5/6 + 1/3