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DENIUS [597]
3 years ago
9

Solve the following proportion for the unknown variable: 15/d = 24/40

Mathematics
2 answers:
Pavel [41]3 years ago
4 0
<span><u><em>Answer:</em></u>
d = 25

<u><em>Explanation:</em></u>
To get the value of d, we will need to isolate the d on one side of the equation.

<u>This can be done as follows:</u>
</span>\frac{15}{d} =  \frac{24}{40}<span>

<u>First, we will do cross multiplication as follows:</u>
40*15 = 24*d
600 = 24d

<u>Then, we will isolate the d as follows:</u>
24d = 600
</span>\frac{24d}{24} =  \frac{600}{24}
<span>
d = 25

Hope this helps :)</span>
solniwko [45]3 years ago
4 0

Answer:

The unknown variable d is, 25

Step-by-step explanation:

Proportion states that two ratios or fractions are equal.

Solve for d:

\frac{15}{d} = \frac{24}{40}

By cross multiply we have;

600 = 24d

Divide both sides by 24 we have;

\frac{600}{24} = d

Simplify:

25 = d

or

d = 25

therefore, the unknown variable d is, 25.

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Answer:77

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3 years ago
Find the area of the region that lies inside the first curve and outside the second curve.
marishachu [46]

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the  the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = \dfrac{1}{2}

\theta = -\dfrac{\pi}{3}, \ \  \dfrac{\pi}{3}

Now, the area of the  region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \  \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \  5^2 d \theta

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \  \theta  d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \   d \theta

A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  \dfrac{cos \ 2 \theta +1}{2}  \end {pmatrix} \ \ d \theta - \dfrac{25}{2}  \begin {bmatrix} \theta   \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}

A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  {cos \ 2 \theta +1}  \end {pmatrix} \ \    d \theta - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}}    \ \ - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{2 \pi}{3} \end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3})  \end {bmatrix} - \dfrac{25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} +   \dfrac{\pi}{3}  \end {bmatrix}- \dfrac{ 25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3}   \end {bmatrix}- \dfrac{ 25 \pi}{3}

A =    \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Download docx
7 0
3 years ago
Help to solve -7 - 3a = 1 - 4a
Evgesh-ka [11]

Answer:

-7 - 3a = 1 – 4a  

Step one: Add 4a to -3a  

 

-7 + a = 1  

 

Step two: Add 7 to 1  

 

A = 8  

 

You're done! A=8 for this problem!  

 

 

Hopefully this helps! Feel free to mark brainliest!  

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4 ft 7 in. < 56 in.
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dolphi86 [110]

Answer:

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Step-by-step explanation:

A: The measures of interior angles of a triangle sum to 180°. Since figure ABC is a triangle, the interior angles of figure ABC sum to 180°.

B: We can see the quadrilateral ACDE is a trapezoid. If you can see, the trapezoid can be split into two triangles if you connect points C and E. As U mentioned before, the measures of interior angles of a triangle sum to 180°. Since we know figure ACDE can be split into <u>two triangles</u> we have to do: 180x2 which is 360°.

C: Now that we know the Pentagon ABCDE can be split into 3 triangles(1 from figure ABC and 2 from figure ACDE), we have to multiply 180 by 3 because like I mentioned before, the measures of interior angles of a triangle sum to 180°. So, 180x3=540°.

5 0
2 years ago
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