Question

Pls do it fast ill mark you brainliest

Answer 1

Answer:

$\sf y=7\frac{2}{3}$ and $\sf x = \frac{2}{3}$

Explanation:

$\sf (1) \ \ (2x+y = 9)$

$\sf (1) \ \ (2x+5y = 37)$

solve for y:

$\sf 2x + y = 9$

$\sf 2x + 5y = 37$

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$\sf 0x + 6y = 46$

$\sf 6y = 46$

$\sf y=\frac{23}{3}$

$\sf y=7\frac{2}{3}$

solve for x:

$\sf 2x + y = 9$

$\sf 2x = 9 - y$

$\sf 2x = 9 - \frac{23}{3}$

$\sf 2x = \frac{4}{3}$

$\sf x = \frac{2}{3}$