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3 years ago

Find the x-coordinates of the points where the graph crosses the x-axis. y = (x - 3)(x + 8)

Mathematics

1 answer:

sleet_krkn [62]3 years ago

6 0

Answer:

The x-coordinates of the points are x = 3 and x = - 8.

Step-by-step explanation:

We have to find the x-coordinates of the points where the graph of equation y = (x - 3)(x + 8) crosses the x-axis.

Now, the x-intercept of a function implies that y = 0 {Because on x-axis, y-value is zero}

Hence, (x - 3)(x + 8) = 0

⇒ (x - 3) = 0 and (x + 8) = 0

⇒ x = 3 and x = - 8

Therefore, the x-coordinates of the points are x = 3 and x = - 8. (Answer)

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Studentka2010 [4]

Answer:

Step-by-step explanation:

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3 years ago

I NEED HELP!! THIS MY FINAL!

barxatty [35]

Answer:

13.5

18.1

72.2

12.8

6,2

66.1

49.1

31.8

Step-by-step explanation:

In solving this question, remember the annotation SOHCAHTOA

1. We are given the value of the hypotenuse and we are to determine the value of the adjacent side. COS would be used to determine this value

Cos 26 = Adjacent / hypotenuse

cos 26 = x / 15

x / 15 =0.8988

x = 15 x 0.8988 = 13.5

2. We are given the value of the hypotenuse and we are to determine the value of the opposite side. SIN would be used to determine this value

Sin = opposite / hypotenuse

sin 49 = x / 24

0.7547 = x / 24

x = 0.7547 x 24

x = 18.1

3. We are given the value of the opposite side and we are to determine the value of the adjacent side. TAN would be used to determine this value

Tan = opposite / adjacent

tan 14 = 18 /x

18 / 0.2493 = 72.2

4. We are given the value of the adjacent and we are to determine the value of the hypotenuse side. COS would be used to determine this value

cos 67 = opposite / hypotenuse

0.3907 = 5/x

x =5/ 0.3907 = 12.8

to determine the missing angle

7. tan^-1 = opposite / adjacent

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4 0

2 years ago

Suppose that two cards are randomly selected from a standard 52-card deck. (a) what is the probability that the first card is

Charra [1.4K]

Hey ,here is the answer to ur question....!
(a).p(that the first card is a queen)=4/52=2/26=1/13
P(the card is a queen if the sampling is done without replacement)=3/52
(B).p(the first card is a queen)=4/52=1/13
P(the second card is queen of the sampling is done with replacement)=1/13....
Hope this helps you....!

8 0

2 years ago

Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)

tigry1 [53]

Answer:

$M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ . Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

$y=k\cdot x + b$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$k$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $b = 1$ , $x = 1$ and $y = 3$ , then we clear slope and solve the resulting expression:

$k = \frac{y-b}{x}$

$k = \frac{3-1}{1}$

$k = 2$

Then, we conclude that point $M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ , whose graph is presented below.

3 0

2 years ago

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

3 years ago