If VX = WZ = 40 cm and m∠ZVX = m∠XWZ = 22°, can ΔVZX and ΔWXZ be proven congruent by SAS? Why or why not?
2 answers:
Answer: The ΔVZX and ΔWXZ are not congruent by SAS.
Explanation:
It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.
Draw a figure as shown below,
According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.
From the given figure it is easily noticed that in ΔVZX and ΔWXZ,
(given)
(given)
(common side)
Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.
Therefore, the ΔVZX and ΔWXZ are not congruent by SAS.
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First, by using the distance formula for just one side, we can find the length of all sides (a square has 4 equal sides.) Then, we can apply the area of a square formula, which is a^2.
Distance formula:
√((-2 + 5)^2 + (-8 + 4)^2)
√((3)^2 + (4)^2)
√9 + 16
√25
5
The side lengths of the square are each equal to 5, and by applying the formula for area, we can find the area of the square.
5^2 = 25
<h3>The area is 25.</h3>