If VX = WZ = 40 cm and m∠ZVX = m∠XWZ = 22°, can ΔVZX and ΔWXZ be proven congruent by SAS? Why or why not?
2 answers:
Answer: The ΔVZX and ΔWXZ are not congruent by SAS.
Explanation:
It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.
Draw a figure as shown below,
According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.
From the given figure it is easily noticed that in ΔVZX and ΔWXZ,
(given)
(given)
(common side)
Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.
Therefore, the ΔVZX and ΔWXZ are not congruent by SAS.
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Answer:
The 95% confidence interval for the percent of all black adults who would welcome a white person into their families is (0.8222, 0.8978).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
323 blacks, 86% of blacks said that they would welcome a white person into their families. This means that
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the percent of all black adults who would welcome a white person into their families is (0.8222, 0.8978).