If VX = WZ = 40 cm and m∠ZVX = m∠XWZ = 22°, can ΔVZX and ΔWXZ be proven congruent by SAS? Why or why not?
2 answers:
Answer: The ΔVZX and ΔWXZ are not congruent by SAS.
Explanation:
It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.
Draw a figure as shown below,
According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.
From the given figure it is easily noticed that in ΔVZX and ΔWXZ,
(given)
(given)
(common side)
Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.
Therefore, the ΔVZX and ΔWXZ are not congruent by SAS.
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2 2/5 feet=12/5 feet.
multiplying them together yields
Part 2:
11.4 ft^2 - 4 1/2 ft^2=
11.4-4.5=6.9 ft^2 = 69/10 ft^2 left after you subtract the decoration in the middle
Now you're trying to find now many rectangular cutouts (that each are 3/8 ft^2) will fit in the remaining space.
You do that by dividing the remaining space left by 3/8:
since you have to have a whole number of cutouts, you round 92/5 down to 90/5, which is 18 cutouts
