All categories

3 years ago

I need help with the break down of finding this answer

Mathematics

1 answer:

larisa [96]3 years ago

8 0

Answer:

Step-by-step explanation:

The formula for the area of a rectangle is length times width. or a=lw.

To find each of the answers you multiply the two numbers.

a) 5(1/3)= 5/3 or $1\frac{2}{3}$ inches squared

b) 5(4/3)= 20/3 or $6\frac{2}{3}$ inches squared

c) 5/2(4/3)=20/6 or $3\frac{1}{3}$ inches squared

d) 7/6(6/7)=56/56 or 1 inch squared

You might be interested in

Is rolling doubles a simple event or compound event

Feliz [49]

The answer to your question is Compound! I think

7 0

3 years ago

Read 2 more answers

9^2= 9.5^2 + 4^2 - 2 (9.5) (4) (cosR) I'm trying to find out the angle measure of R

alexandr402 [8]

Sorry I can't solve it.

Firstly, the equation is wrong. It is supposed to be 81 ≠ 30.25

Second of all, this is the best I got 81= −76 (cos(r) + 106.25

5 0

3 years ago

What is the simplified form of 12x/900x²y4z6?

zalisa [80]

Answer:

$360xy^2|xz^3|$

Step-by-step explanation:

Given expression:

$12x \sqrt{900x^2y^4z^6}$

$\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:$

$\implies 12x \sqrt{900}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

Replace 900 with 30² :

$\implies 12x \sqrt{30^2}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

$\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:$

$\implies 12x \cdot 30|x|\sqrt{y^4}\sqrt{z^6}$

$\implies 360x|x|\sqrt{y^4}\sqrt{z^6}$

(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).

$\textsf{Apply exponent rule} \quad \sqrt{a^m}=a^{\frac{m}{2}}:$

$\implies 360x|x|\cdot y^{\frac{4}{2}}\cdot z^{\frac{6}{2}}$

Simplify:

$\implies 360xy^2|xz^3|$

(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).

7 0

2 years ago

(5+2yi)(4-3i)-4(5+2yi)

lesya [120]

If you download Photomath and scan your question it will give u the answer;)

6 0

3 years ago

The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =

madreJ [45]

So we are given a system:
$3x-2y+3z=0\\
-3x - 5y - 5z= -21$
Substitute x = 2 we get the system:
$-2y+3z=-6\\
- 5y - 5z= -15$
Multiply the first equation by -5 and the second by 2 we get the system:
$10y-15z=30\\
- 10y - 10z= -30$
Adding the two equations we get :
$-25z=0\text{ then}z=0.$
We find the value of y by using any of the other equations like this:
$-2y=-6\\y=3.$
Final solution:
$z=0,y=3$

8 0

3 years ago

Read 2 more answers