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yanalaym [24]
3 years ago
9

NEED THE ANSWER ASAP, PLEASE HELP!! What are the coordinates of the focus of the parabola?

Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

Vertex is (-8, 4)  not one of the answers offered!

Step-by-step explanation:

Factor -1/8 out of the first two terms. Leave a space inside parentheses in which to add a number.

y=-\frac{1}{8}(x^2 + 16x + \text{-----})-4

Complete the square by squaring half the coefficient of <em>x </em>and adding it in the space.

(\frac{16}{2})^2=64

Add 64 in the space you made, then compensate for that at the end of the expression by <u>subtracting</u>  -\frac{1}{8}(64)=-8

y=-\frac{1}{8}(x^2+16x+64)-4+8\\y=-\frac{1}{8}(x+8)^2+4

The x-coordinate of the vertex is the <u>opposite</u> of +8, the number inside the parentheses.  The y-coordinate of the vertex is the number at the end of the expression.

V(-8, 4)

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