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DerKrebs [107]
3 years ago
8

A force of 125 newtons stretches a spring 0.15 meters. What force is required to stretch it 0.25 meters??

Mathematics
1 answer:
Ilya [14]3 years ago
4 0

Answer:

Step-by-step explanation:

A spring has a force formula of F = k*x

f = 125 N

x = 0.15 m

125 = k*0.15

k =833.33

F = ?

k = 833.33

x = 0.25 m

F = 833.33 * 0.25

F = 208.33 N

You could do this without solving for k

F1/F2 = x1/x2

F1 = 125 N

F2 = ?

x1 = 0.15

x2 =0.25

125 / F2 = 0.15 / 0.25               Cross multiply

125 * 0.25 = 0.15 * F2              Divide by 0.15

125*0.25 /0.15 = F2

F2 = 208.33 just as you got above

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Which is greater 0.25 or 0.025
storchak [24]

Answer:

0.25

Step-by-step explanation:

0.25*100=25

0.05*100=5.25

25 is greater than 5.25 so 0.25 is your answer

Hope this helps :) and pls give brainliest

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Step-by-step explanation:

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Here are the equation steps:

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Bingel [31]
Well, to find u, we have to remove all that is attached to it so the equation can just be u=...
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