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Darya [45]
3 years ago
8

Starting from rest, approximately how far does an object fall freely in 3 seconds?

Physics
1 answer:
Sergio039 [100]3 years ago
8 0
Hi! In 3 seconds the object will fall approximately 44 meters.
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diverging light rays of the bulb are collected by the reflector.

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a mass of 0.75 kg is attached to a spring and placed on a horizontal surface. the spring has a spring constant of 180 N/m, and t
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Answer:

6.57 m/s

Explanation:

First use Hook's Law to determine the F the compressed spring acts on the mass. Hook's Law F=kx; F=force, k=stiffnes of spring (or spring constant), x=displacement

F=kx; F=180(.3) = 54 N

Next from Newton's second law find the acceleration of the mass.

Newton's .2nd law F=ma; a=F/m ; a=54/.75 = 72m/s²

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v₂²= v₀² + 2a(x₂-x₀); v₂=final velocity; v₀=initial velocity; a=acceleration; x₂=final displacement; x₀=initial displacment.

v₀=0, since the mass is at rest before we release it

a=72 m/s² (from above)

x₀=0 as the start position already compressed

x₂=0.3m (this puts the spring back to it's natural length)

v₂²= 0 + 2(72)(0.3) = 43.2 m²/s²

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3 years ago
If your apparatus were to be dropped from a mile above the ground, describe the forces acting upon your apparatus as it fell. Ho
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Explanation:

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2 years ago
Use double replacement and combustion reaction in a sentence
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Answer:

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A 4.0 cm × 4.2 cm rectangle lies in the xy-plane. You may want to review (Pages 664 - 668) . Part A What is the electric flux th
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Answer:

(A). The flux is 0.336 N.m²/C

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Explanation:

Given that,

Length = 4.2 cm

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Area vector is perpendicular to xy plane

(A). We need to calculate the flux

Using formula of flux

\phi=E\cdot A

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A = area

Put the value into the formula

\phi=(150 i-200 k)\times(4.2\times10^{-2}\times4.0\times10^{-2})k

\phi=-200\times4.2\times10^{-2}\times4.0\times10^{-2}

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E=(150i-200j)\ N/C

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Using formula of flux

\phi=E\cdot A

Put the value into the formula

\phi=(150 i-200 j)\times(4.2\times10^{-2}\times4.0\times10^{-2})k

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