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kap26 [50]
4 years ago
12

Starting from rest, a particle that is confined to move along a straight line is accelerated at a rate of 5.0 m/s2. Which one of

the following statements concerning the slope of the position versus time graph for this particle is true? a) The slope is not constant and decreases with increasing time. b) The slope has a constant value of 5.0 m/s. The slope has a constant value of 5.0 m/s2. c) The slope is not constant and increases with increasing time. d) The slope is both constant and negative.
Physics
1 answer:
Elanso [62]4 years ago
6 0

Answer:

c) The slope is not constant and increases with increasing time.

Explanation:

The equation for the position of this particle (starting from rest is)

s = at^2/2 = 5t^2/2 = 2.5t^2

We can take derivative of this with respect to time t to get the equation of slope:

s' = (2.5t^2)' = 2*2.5t = 5t

As time t increase, the slope would increases with time as well.

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Are scientific theories and laws developed in the acquisition of scientific knowledge
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3 years ago
On May 26, 1934, a streamlined, stainless steel diesel train called the Zephyr set the world’s nonstop long-distance speed recor
Andre45 [30]

Answer:

124.88 km/h

34.69 m/s

Explanation:

1633.8 km = 1633800 m

13 hours 4 minutes 58 seconds = 13 + 4/60 + 58/3600 = 13.083 hours

13 hours 4 minutes 58 seconds = 13*3600 + 4*60 + 58 = 47098 seconds

So the average speed in km/h is

1633.8 / 13.083 = 124.88 km/h

The average speed in m/s is

1633800 / 47098 = 34.69 m/s

8 0
3 years ago
A 2.00 kg object is moving in a circular path with a radius of 5.00 cm. The object starts from rest and with constant angular ac
Rom4ik [11]

Answer:

0.800 m/s²

Explanation:

First, calculate the angular acceleration:

ω = αt + ω₀

6.00 rad/s = α (3.00 s) + 0 rad/s

α = 2.00 rad/s²

Now calculate the angular velocity at t = 2.00 s:

ω = αt + ω₀

ω = (2.00 rad/s²) (2.00 s) + 0 rad/s

ω = 4.00 rad/s

Calculate the linear velocity:

v = ωr

v = (4.00 rad/s) (0.0500 m)

v = 0.200 m/s

Finally, calculate the centripetal acceleration:

a = v² / r

a = (0.200 m/s)² / (0.0500 m)

a = 0.800 m/s²

3 0
3 years ago
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