An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis.
1 answer:
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Answer:
Force,
Explanation:
Given that,
Mass of the bullet, m = 4.79 g = 0.00479 kg
Initial speed of the bullet, u = 642.3 m/s
Distance, d = 4.35 cm = 0.0435 m
To find,
The magnitude of force required to stop the bullet.
Solution,
The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :
Finally, it stops, v = 0
F = -22713.92 N
So, the magnitude of the force that stops the bullet is
Answer:
Explanation:
Given
Radioactive material is found to decrease 40% of its original value in
Sample at any time is given by
where,
Put values
Taking natural logarithm both side
Answer:
2 m/s²
Explanation:
velocity =
20/10 = 2