Answer:
I don't understand what you are looking for
Step-by-step explanation:
If a number can only be divided by 1 and itself it is prime, but if it is composite, it can be divided evenly by numbers other than 1 and itself.
63 can be divided by 3 and 21, so it is a composite number.
Answer:
The value of k is greater than or equal to 0, i.e. k≥7.
Step-by-step explanation:
The given equation is
The value of k must be a positive integer because k! is defined for k≥0, where k∈Z.
Subtract 48 from both the sides.
Using , we get
Divide both sides by 48k.
Note: The value of m can be 0 or 1.
The value of k is positive integer, so the right hand side of the above equation must be a positive integer.
Since RHS of the equation is positive integer, therefore (k-1)! is completely divisible by 48.
Add 1 on both sides.
Therefore the value of k is greater than or equal to 0.
Hello from MrBillDoesMath!
Answer:
y^2-5y -4
Discussion:
The problem asks us to find the polynomial, g(y), such that
y^2-5y + 1 - g(y) = 5 => (add g(y) to both sides)
y^2 -5y + 1 - g(y) + g(y) = 5 + g(y) =>
y^2 -5y + 1 + 0 = 5 + g(y) => (as -g(y) + g(y) = 0)
Finally subtract 5 from both sides:
y^2 - 5y + 1 -5 = (5 -5 ) + g(y) =>
y^2-5y -4 = g(y)
Thank you,
MrB
Answer:
1.199 ≤ x ≤ 1.201
Step-by-step explanation:
You want ...
|y -7| ≤ 0.005
Substituting the expression for y, you have ...
|5x+1 -7| ≤ 0.005
|x -1.2| ≤ 0.001 . . . . . simplify, divide by 5
-0.0001 ≤ x -1.2 ≤ 0.001 . . . . . "unfold" the absolute value
1.199 ≤ x ≤ 1.201 . . . . . . . . . . . .add 1.2