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2 years ago

What's 0.875 as a fraction in simplest form

Mathematics

1 answer:

zhenek [66]2 years ago

8 0

$0.875=\dfrac{875}{1000}=\dfrac{875:25}{1000:25}=\dfrac{35:5}{40:5}=\boxed{\frac{7}{8}}$

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Which products result in a difference of square or perfect square trinomial? Plzzz help quick!!

vagabundo [1.1K]

Answer:

perfect square: 2, 5
difference of squares: 1, 6

Step-by-step explanation:

If the two factors are identical, their product will be a perfect square.

If one of the factors is the difference of terms that are summed in the other factor, the product will be the difference of squares.

(a +b)(a -b) = a² -b² . . . . . matches the 1st and 6th choices

(a +b)(a +b) = (a +b)² . . . . matches the 2nd and 5th choices

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2 years ago

12. What is the measure of angle J in the triangle below? Drawing is not to scale. (1 point)

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Answer: D. 48 degrees.

Step-by-step explanation:

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2 years ago

Calculate the quotient below and give your answer in scientific notation.

ELEN [110]

Answer: 8.16•10^2

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

. The sign of the exponent will depend on the direction you are moving the decimal. You do this to both equations and when you got the final answer of you divide the 2 equations and put it back in scientific notation Mark me brainliest

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2 years ago

Read 2 more answers

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

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3 years ago

Hi i need help with this

ICE Princess25 [194]

The range would be [-4, infinity) because range is the y-value. The lowest y-value is -4. The greatest y-value goes up to infinity.

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3 years ago