Answer:
Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq)
1.35 V
Explanation:
Given that the reduction potential of
Cu^2+(aq) + e- -----> Cu^+(aq) is +0.15 V
While the reduction potential of
Au3+(aq) + 3 e- -----> Au(s) is + 1.50V
It is clear that the Cu^+(aq)/Cu^2+(aq) system is the anode while Au^3+(aq)/Au(s) system is the cathode based on the reduction potentials shown above. The number of electrons transferred (n) =3
E°cell = E°cathode - E°anode
E°cell= 1.50-0.15
E°cell= 1.35 V
<u>Answer:</u> The volume of concentrated hydrochloric acid solution is 1.73 mL
<u>Explanation:</u>
To calculate the hydrogen ion concentration of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
pH = 1.60
Putting values in above equation, we get:
![1.60=-\log [H^+]](https://tex.z-dn.net/?f=1.60%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=10^{-1.60}=0.0251M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-1.60%7D%3D0.0251M)
To calculate the volume of the concentrated solution, we use the equation:

where,
are the molarity and volume of the concentrated HCl solution
are the molarity and volume of diluted HCl solution
We are given:

Putting values in above equation, we get:

Hence, the volume of concentrated hydrochloric acid solution is 1.73 mL
Answer:
The pH of solution is 2.88 .
Explanation:
The reaction is :

We know,
for this reaction is = 
Also, since volume of water is 1 L.
Therefore, molarity of solution is equal to number of moles.
Also, ![K_a=\dfrac{[CH_3COO^-][H^+]}{[CH_3COOH]}](https://tex.z-dn.net/?f=K_a%3D%5Cdfrac%7B%5BCH_3COO%5E-%5D%5BH%5E%2B%5D%7D%7B%5BCH_3COOH%5D%7D)
Let, amount of
produce is x.
So,
![K_a=\dfrac{[x][x]}{[0.1]}\\1.76\times 10^{-5}=\dfrac{[x][x]}{[0.1]}](https://tex.z-dn.net/?f=K_a%3D%5Cdfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.1%5D%7D%5C%5C1.76%5Ctimes%2010%5E%7B-5%7D%3D%5Cdfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.1%5D%7D)

We know, 
Therefore, pH of solution is 2.88 .
Hence, this is the required solution.
1.Joule
2.Kelvin
3.Gram
4.Meter