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3 years ago

What is the pOH of a 0.0010 M solution of calcium hydroxide (Ca(OH)2)

Chemistry

1 answer:

inysia [295]3 years ago

7 0

Answer: The pOH is: " 2.40 " .

__________________________________________________________

The pOH value of a 0.0010 M solution of calcium hydroxide;

Ca(OH)₂ ; is:

__________________________________________________________

" 2.40 " .

__________________________________________________________

Explanation:

___________________________________________________________

Calculate the pOH of a 0.0010 M solution of Ca(OH)₂ .

Note that:

"M" represents the concentration in "Molarity" ;

(that is; "moles of solute per Liter of solution" ; or, "mol / L " } ;

and that for our purposes, anything notes in "brackets" refers to "concentration"; in "M" {"Molarity" ; as explained above.}.

Note that "calcium hydroxide", that is; " Ca(OH)₂ " ;

→ dissociates into the following ions, as follows:

→ Ca(OH)₂ → Ca²⁺ + 2 OH⁻ ;

Therefore, the [OH⁻] equals: {2 * 0.0010} M = 0.0040 M .

For every Ca(OH)₂ you produce 2 OH⁻ .

<u>Note</u>: pOH = - log [OH⁻] ;

pOH = - log ( 0.0040) = 2.3979400086720375 ;

→ round to: " 2.40 " .

__________________________________________________________

Answer: The pOH is: " 2.40 " .

__________________________________________________________

The pOH value of a 0.0010 M solution of calcium hydroxide; Ca(OH)₂ ; is:

" 2.40 " .

__________________________________________________________

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