All categories

4 years ago

Which model best illustrates Thomson’s explanation of the atom? Answers in the picture.

Chemistry

2 answers:

Tomtit [17]4 years ago

7 0

pluses and negatives

D) because it has negative and positive signs

myrzilka [38]4 years ago

5 0

Answer:

D. This D one model best illustrates Thomson explanation of atom

Explanation:

You might be interested in

A clear colorless liquid in an open beaker was heated to boiling. The liquid began to boil at 110°C, and as vapors escaped, the

Vaselesa [24]

Omitted options and they are

a) pure compound.

b. pure element.

c. pure substance.

d. homogeneous solution.

e. heterogeneous solution

Answer:d. homogeneous solution.

Explanation:

Pure substances or elements or compounds have a definite and sharp melting or boiling point, Any substance that is not pure is impure and will have different temperature of melting or boiling points.

To this effect, the clear colorless liquid cannot be a Pure substance, element or compound.

We can therefore say that the clear colorless liquid would be a homogeneous solution because a homogeneous solution is a mixture of constituents which completely mixes together such that each constituents cannot be seen with naked eye, When heated to boiling, each constituent in the mixture will give different boiling points.

A heterogeneous Solution, too is a mixture but contains constituents that can be seen and not a clear colourless solution.

Therefore On the basis of this information, we can say that the material in the beaker was a Homogeneous solution

8 0

4 years ago

When correctly balanced using the smallest whole number coefficients, what is the coefficient of copper in the following formula

yan [13]

The answer is 2. this makes the equation 2Cu + S8 —> Cu2S

4 0

3 years ago

A sample of gas contains 0.1900 mol of CO(g) and 0.1900 mol of NO(g) and occupies a volume of 22.0 L. The following reaction tak

worty [1.4K]

Answer:

V₂ = 16.5 L

Explanation:

To solve this problem we use <em>Avogadro's law, </em>which applies when temperature and pressure remain constant:

V₁/n₁ = V₂/n₂

In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].

n₁ = mol CO + mol NO = 0.1900 + 0.1900 = 0.3800 mol

<em>We use the reaction to calculate n₂</em>:

2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)

mol CO₂:

0.1900 mol CO * $\frac{2molCO_{2}}{2molCO} =$ 0.1900 mol CO₂

mol N₂:

0.1900 mol NO * $\frac{1molN_{2}}{2molNO} =$ 0.095 mol N₂

n₂ = mol CO₂ + mol N₂ = 0.1900 + 0.095 = 0.2850 mol

Calculating V₂:

22.0 L / 0.3800 mol = V₂ / 0.2850 mol

V₂ = 16.5 L

3 0

4 years ago

Plz, Help :/ you can choose any question you want or all of it if you pleased.

Mnenie [13.5K]

Answer:

29. Proteins support the body's structural framework, chemical reactions, and contractions (muscle movement).

30. Proteins have a primary structure (polypeptide chain of amino acids), secondary structure (made up of alpha helices and beta pleat sheets), tertiary structure (superimposed on secondary structure), and quaternary structure (2 or more polypeptide chains with its own tertiary structure).

31. Protein molecules can denature if conditions aren't right, such as the wrong temperature or pH level. When denatured, proteins typically lose their shape and their function for a short time because their active sites become deactivated (though if conditions are too extreme, they can permanently lose their function). This happens to globular proteins because they are not nearly as stable as fibrous proteins due to their functional 3D shape.

I just did the first 3 since I could easily access the proteins section in my textbook at the moment. :)

5 0

3 years ago

A chemistry student in lab needs to fill a temperature-control tank with water. The tank measures 24.0 cm long by 21.0 cm wide b

Natalija [7]

Answer:

The required volume of water the student needs is 4.9 litres of water

Explanation:

From the diagram related to the question, we have;

The dimensions of the tank are;

Length of tank = 24.0 cm = 0.24 m

Width of tank = 21.0 cm = 0.21 m

Depth of tank = 13.0 cm. = 0.13 m

Allowance provided between the top of the tank and the top of the water = 2.0 cm

Diameter of the round bottom flask, D = 10.5 cm = 0.105 m

Therefore, the radius of the round bottom flask, r = 0.105/2 = 0.0525 m

Therefore we have;

Depth of water in the tank = Depth of tank - Allowance provided between the top of the tank and the top of the water

∴ Depth of water in the tank = 13.0 - 2.0 = 11.0 cm = 0.11 m

Given that the flask is immersed in the water contained in the tank to raise the tank water level, we have;

Volume of water + Volume of flask in the tank = Length of tank × Width of tank × Depth of water in the tank

Volume of water + Volume of flask in the tank = 0.24 × 0.21 × 0.11 = 0.005544 m³ = 0.005544 m³× 1000 l/m³ = 5.544 l

The volume of the spherical flask = 4/3·π·r³ = 4/3·π·0.0525³ = 6.06×10⁻⁴ m³ = 6.06×10⁻⁴ m³ × 1000 l/m³ = 0.606 l

The required volume of water the student needs , V = Volume of water + Volume of flask in the tank - The volume of the spherical flask = 5.544 l - 0.606 l = 4.9 l.

6 0

3 years ago