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Trava [24]
2 years ago
8

How many joules of heat are needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of alu

minum is 0.90 J/g°C?
Chemistry
1 answer:
USPshnik [31]2 years ago
6 0

Answer: There are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.

Explanation:

Given: Mass = 30.0 g

Specific heat = 0.90 J/g^{o}C

T_{1} = 22^{o}C

T_{2} = 80^{o}C

Formula used to calculate the heat energy requires is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat capacity of substance

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 30.0 g \times 0.90 J/g^{o}C \times (80 - 22)^{o}C\\= 1566 J

Thus, we can conclude that there are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.

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If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g・°C) that can be heated from 22.5°C to
inysia [295]

Answer:

The correct answer will be "18.25 g".

Explanation:

The given values are:

Specific heat,

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Heat involved,

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Temperature,

ΔT = 120.0°C-22.5°C

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As we know,

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On substituting the given values, we get

⇒  0.45=\frac{801}{m(97.5)}

⇒  m = 18.25 \ g

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