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Trava [24]
3 years ago
8

How many joules of heat are needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of alu

minum is 0.90 J/g°C?
Chemistry
1 answer:
USPshnik [31]3 years ago
6 0

Answer: There are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.

Explanation:

Given: Mass = 30.0 g

Specific heat = 0.90 J/g^{o}C

T_{1} = 22^{o}C

T_{2} = 80^{o}C

Formula used to calculate the heat energy requires is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat capacity of substance

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 30.0 g \times 0.90 J/g^{o}C \times (80 - 22)^{o}C\\= 1566 J

Thus, we can conclude that there are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.

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mole ratio of hydrazine to Nitogen is     1   :  1
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then mass of hydrazine      = 0.165 × (14 × 2)
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Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib
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<u>Answer:</u> The value of K_c for the final reaction is 7.16\times 10^{25}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1

<u>Equation 2:</u>  HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2

The net equation follows:

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The value of equilibrium constant for net reaction is:

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Putting values in above equation, we get:

K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}

Hence, the value of K_c for the final reaction is 7.16\times 10^{25}

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