1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
choli [55]
3 years ago
15

Which two values will a spontaneous reaction have?

Chemistry
2 answers:
Dafna11 [192]3 years ago
8 0

Answer:

-∆G and +Eocell

Explanation:

For an electrochemical reaction to be spontaneous, the change in free energy must be negative. This applies to all chemical reactions as a basic condition for spontaneity of chemical reactions.

More particular to an electrochemical cell is the value of the standard cell voltage. A positive value of standard cell voltage implies a spontaneous electrochemical reaction.

Agata [3.3K]3 years ago
6 0
<span>-∆G and +Eocell are </span>spontaneous.

Always Remember: The higher the value of the EMF of a cell then it means the driving force for the reaction to occur is also high.
 
Hope this Helps! ;)
You might be interested in
Yasmin's teacher tells her that the solubility of salt is 360 g/L at room temperature (25 °C). How can Yasmin make an unsaturate
Bezzdna [24]

Answer:

By adding less amount or quantity of the salt (solute), than the medium (solvent) can dissolve at a particular temperature that is to make an unsaturated solution at room temperature, Yasmin should add less than 360 g of salt to one liter of the solvent

Explanation:

An unsaturated solution is one that consists of less than the maximum mass or quantity of the solute that it is capable of dissolving.

6 0
3 years ago
Which carbon reservoirs are underutilized
statuscvo [17]
Carbon is stored in the ocean
8 0
3 years ago
When a student chemist transferred the metal to the calorimeter, some water splashed out of the calorimeter. will this technique
Natalka [10]

Answer:

It will be reported too low.

Explanation:

To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.

Qmetal + Qwater = 0

Qmetal = -Qwater

The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:

m_metal*s*ΔT_metal = - m_water *c*ΔT_water

s = -m_water *c*ΔT_water / m_metal*ΔT_metal

So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.

5 0
3 years ago
A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s
Alla [95]

<u>Answer:</u> The percent yield of the 1-bromobutane is 48.65 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For NaBr:</u>

Given mass of NaBr = 11.1 g

Molar mass of NaBr = 103 g/mol

Putting values in equation 1, we get:

\text{Moles of NaBr}=\frac{11.1g}{103g/mol}=0.108mol

The chemical equation for the reaction of 1-butanol and NaBr is:

\text{1-butanol + NaBr}\rightarrow \text{1-bromobutane}

By Stoichiometry of the reaction

1 mole of NaBr produces 1 mole of 1-bromobutane

So, 0.108 moles of NaBr will produce = \frac{1}{1}\times 0.108=0.108 moles of 1-bromobutane

  • Now, calculating the mass of 1-bromobutane from equation 1, we get:

Molar mass of 1-bromobutane = 137 g/mol

Moles of 1-bromobutane = 0.108 moles

Putting values in equation 1, we get:

0.108mol=\frac{\text{Mass of 1-bromobutane}}{137g/mol}\\\\\text{Mass of 1-bromobutane}=(0.108mol\times 137g/mol)=14.80g

  • To calculate the percentage yield of 1-bromobutane, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of 1-bromobutane = 7.2 g

Theoretical yield of 1-bromobutane = 14.80 g

Putting values in above equation, we get:

\%\text{ yield of 1-bromobutane}=\frac{7.2g}{14.80g}\times 100\\\\\% \text{yield of 1-bromobutane}=48.65\%

Hence, the percent yield of the 1-bromobutane is 48.65 %

5 0
3 years ago
In the chemical equation Zn + 2HCL -----&gt; ZnCl2 + H2
Norma-Jean [14]
Zinc and hydrochloric
3 0
3 years ago
Other questions:
  • Explain the relationship between forward and backward reactions in equilibrium, and predict how changing the amount of a reactan
    9·2 answers
  • Rosa parks peaceful act of defiance answers
    13·1 answer
  • Which is the top layer of groundwater?
    14·2 answers
  • Which formula contains two nonmetals
    14·1 answer
  • Which of the following is NOT a good way to reduce pollutants in paint shops? A) Use extra topcoat color to get better coverage
    14·1 answer
  • Which option should a person avoid doing in order to better protect the quality of watersheds?
    15·1 answer
  • What do you call all water on earth surface
    7·1 answer
  • What is the density of fluorine gas, F2, at STP? E) 0.848 g/L B) 1.18 g/ L C ) 1.70 g/L D) 0.589 g/L
    15·1 answer
  • Is orange juice a element or a mixture
    5·2 answers
  • 5. Explain why both diet and regular soft drinks can<br> damage the enamel on the surface of teeth.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!