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Anna35 [415]
3 years ago
5

Given the following measurements, calculate the minimum and maximum possible object. Round to the nearest square whole square un

it.
The length of and width of a bookcover 22.2 centimeters and 12 Ret centimeters, respectively.​
Mathematics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

28.3 centimeters and 21 centimeters

Step-by-step explanation:

28.3 + 0.05) cm, so 28.25 cm ≤ length < 28.35 cm.

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1/5 ÷ 2. simple for a couple of points lol
Sergio039 [100]

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Rudolfo wants to save his allowance in his own bank account. Given that his principal amount ₱20 000 with 1.5% monthly interest
xeze [42]

Answer:

Step-by-step explanation:

P = 20,000

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4 0
3 years ago
Find 59.2% of 250...................................
Katarina [22]

Answer:

148

Step-by-step explanation:

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5 0
3 years ago
If angle∠ A and angle∠ B are supplementary angles and angle∠ A is eighteight times as large as angle∠ ​B, find the measures of a
Shalnov [3]
A = 8B
A + B = 180
8B + B = 180
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4 0
3 years ago
if a tv has a diagonal measurement of 55 and a height of 30, what is the tvs width? round to the nearest whole number
Sati [7]

Answer:

  46

Step-by-step explanation:

The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.

__

<h3>Pythagorean theorem</h3>

The relation between the leg lengths (a, b) and the hypotenuse (c) is ...

  c² = a² +b²

Solving for b gives ...

  b = √(c² -a²)

<h3>application</h3>

In this problem, we have c=55 and a=30. Then the width of the TV is ...

  b = √(55² -30²) = √(3025 -900) = √2125

  b ≈ 46.098

The width of the TV is about 46.

7 0
2 years ago
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