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Anna35 [415]
3 years ago
5

Given the following measurements, calculate the minimum and maximum possible object. Round to the nearest square whole square un

it.
The length of and width of a bookcover 22.2 centimeters and 12 Ret centimeters, respectively.​
Mathematics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

28.3 centimeters and 21 centimeters

Step-by-step explanation:

28.3 + 0.05) cm, so 28.25 cm ≤ length < 28.35 cm.

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Two beakers plus their contents have a mass of 180.4 grams. The total mass of the contents is 56.8 grams. Write and solve an equ
Anika [276]
I don't know if I am right but I think this is the answer:
If we write beaker with x and content with y
then y=56.8/2=28.4   this is the content of one beaker
so there are two beakers:
2x+28.4=180.4
2x=180.4-28.4
2x=152/2
x=76   
6 0
3 years ago
5
murzikaleks [220]

Answer:

From my research, the coordinate points can be found on image below. Since N is the reflection of B and O is the reflection of C, if we were to draw a line to the right of N and a vertical line below C, the point of intersection of these two lines should give us the location of point O. Doing just that, point O is found at (5,5).

Step-by-step explanation:

Hope I helped You :) have a good day.

6 0
3 years ago
Read 2 more answers
Will mark as brainliest if answer is correct
ryzh [129]

Answer:

B

Step-by-step explanation:

The term in the () is usually the x coordinate, and the last term (-1) is usually the y coordinate.

7 0
2 years ago
How many ml of 1:4 solution and how many ml of sterile water are needed to prepare 600 ml of 1:20 solution ?
Delvig [45]

Answer:

Approximately 143 mL of 1:4 solution and 457 mL of water

Step-by-step explanation:

A 1:4 solution has a concentration of 1/(1+4) = 1/5 or 20%.

Similarly, a 1:20 solution has a concentration of 1/(1+20) = 1/21 or 4.76%.

If x is the mL of 20% solution and y is the mL of water, then:

x + y = 600

1/5 x = 1/21 (600)

Solve:

x = 5/21 (600)

x ≈ 143

y ≈ 457

You need approximately 143 mL of 1:4 solution and 457 mL of water.

4 0
3 years ago
A homeowner installs a solar heating system, which generates 20 savings at a rate of 300e t dollars per year, t years after inst
bazaltina [42]

Answer:

"35.84 years" is the appropriate solution.

Step-by-step explanation:

The given values are:

Rate of savings generation,

s'(t)=300e^{\frac{t}{20} }

System cost to install,

= $30000

Now,

The total savings will be:

⇒  s(t)=\int\limits s'(t) \ dt

On substituting the values, we get

⇒         = \int\limits 300e^{\frac{t}{20} } \ dt

⇒  s(t)=\frac{300e^{\frac{t}{20} }}{\frac{1}{20} }+c

When,

Savings = 0

t = 0, then

⇒  0=6000e^o+c

⇒  c=-6000

The formula will be:

⇒  s(t)=6000[e^{\frac{t}{20} }-1]

On putting the values in the above formula, we get

⇒  30000=6000(e^{\frac{t}{20} }-1)

           5=e^{\frac{t}{20}}-1

        e^{\frac{t}{20} }=6

On taking log, we get

⇒  \frac{t}{20} =log \ 6

      t=20 log 6

        =35.84 \ years  

7 0
3 years ago
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