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3 years ago

Complete the point-slope equation of the line through (-4,8) and (4,4)

Mathematics

2 answers:

Dahasolnce [82]3 years ago

8 0

I use a slope calculator so im not sure if it right but here you go!

notka56 [123]3 years ago

4 0

Answer:

y-4=(-1/2)(x-4)

Step-by-step explanation:

Slope=(8-4)/(-4-4)=-4/8=-1/2

The equation of the line is y-4=(-1/2)(x-4)

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In a competitive examination negative marks of 2 are awarded for each wrong answers and 4 marks for every correct answer. If nee

Alex777 [14]

9514 1404 393

Answer:

Rajan gets 6 marks more

Step-by-step explanation:

Neerav's marks are (15)(4) +(5)(-2) = 60 -10 = 50.

Rajan's marks are (14)(4) = 56.

Rajan gets 6 more marks than Neerav.

3 0

2 years ago

Is (-2,-6) a solution of y < 7x + 8?

mojhsa [17]

Answer:

not a solution

Step-by-step explanation:

y < 7x + 8

Substitute (2-,-6) into the inequality

-6 < 7(-2) +8

-6 <-14+8

-6 <-6

This is not true because they are equal not less than

6 0

3 years ago

Read 2 more answers

What is the solution to 2(-4x+1)=2/3(x+2)

Rzqust [24]

Hello!

The answer to your problem is: $x=1/13$

Simplify both sides of the equation

$(2)(-4x)+(2)(1)=(2/3)(x)+(2/3)(2)$ $(Distribute)$

$-8x+2=2/3x+4/3$

Subtract 2/3x from both sides

$-8x+2-2/3x=2/3+4/3-2/3x$

$-26x+2=4/3$

Subtract 2 from both sides

$-26/3x+2-2=4/3-2$

$-26/3=-2/3$

Multiply both sides by 3/(-26)

$(3/26)*(-26/3x)=(3/-26)*(-2/3)$

Get your answer

$x=1/13$

Hope This Helps!

8 0

3 years ago

I need help ASAP will mark you the brainliest

Leokris [45]

Answer:

Step-by-step explanation:

longer leg/shorter leg = longer leg/shorter leg

10/5 = 5/2.5

8 0

3 years ago

Find the derivative of the function at P 0 in the direction of A. f(x,y,z) = 3 e^x cos(yz), P0 (0, 0, 0), A = - i + 2 j + 3k

Alik [6]

The derivative of $f(x,y,z)$ at a point $p_0=(x_0,y_0,z_0)$ in the direction of a vector $\vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k$ is

$\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}$

We have

$f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k$

and

$\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}$

Then the derivative at $p_0$ in the direction of $\vec a$ is

$3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}$

3 0

3 years ago