Given:
The function is
![f(x)=\dfrac{8\sqrt[3]{x}-8}{9}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac%7B8%5Csqrt%5B3%5D%7Bx%7D-8%7D%7B9%7D)
To find:
The inverse function
.
Solution:
We have,
![f(x)=\dfrac{8\sqrt[3]{x}-8}{9}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac%7B8%5Csqrt%5B3%5D%7Bx%7D-8%7D%7B9%7D)
Step 1: Putting f(x)=y, we get
![y=\dfrac{8\sqrt[3]{x}-8}{9}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B8%5Csqrt%5B3%5D%7Bx%7D-8%7D%7B9%7D)
Step 2: Interchange x and y.
![x=\dfrac{8\sqrt[3]{y}-8}{9}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B8%5Csqrt%5B3%5D%7By%7D-8%7D%7B9%7D)
Step 3: Isolate variable y.
![9x=8\sqrt[3]{y}-8](https://tex.z-dn.net/?f=9x%3D8%5Csqrt%5B3%5D%7By%7D-8)
![9x+8=8\sqrt[3]{y}](https://tex.z-dn.net/?f=9x%2B8%3D8%5Csqrt%5B3%5D%7By%7D)
![\dfrac{9x+8}{8}=\sqrt[3]{y}](https://tex.z-dn.net/?f=%5Cdfrac%7B9x%2B8%7D%7B8%7D%3D%5Csqrt%5B3%5D%7By%7D)
Taking cube on both sides, we get


Step 4: Putting
, we get

Therefore, the correct option is C.
Answer:
i dont understand
Step-by-step explanation:
oh wait... (0,0) (16,28) (0,33)
First you have multiply 6 by both 3x and 8
6*3x = 18x
6*8= 48
18x + 48 + 32 + 12x
now combine like terms
18x + 12x = 30x
48 + 32 = 80
so 30x + 80 is your answer
T_n = 3 * T_(n-1)
Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1
T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!
Short way (sometimes it works!)
T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648