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3 years ago

What is another way to write -3 x (4+7)

Mathematics

1 answer:

atroni [7]3 years ago

8 0

Answer:

Step-by-step explanation:

-3 x (4+7)

-12 -21

=-33

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Evaluate -41-41.=<br> -8<br> 08<br> 16<br> -16

Alex Ar [27]

Answer:

are you sure those are all the options because it is -82

Step-by-step explanation:

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2 years ago

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Find the length of the second base of a trapezoid with one base measuring 12 ft, a height of 4 ft, and an area of 58 square ft.

aleksandrvk [35]

The second base would be 17 feet.
To find the area of a trapezoid it is (base1 + base2) height
__________________
2

3 0

3 years ago

What sequence is modeled by the graph below?

Lady bird [3.3K]

ANSWER

$a_n= \frac{1}{2}( {2}^{n - 1} )$

EXPLANATION

The corresponding ordered pairs from the graph are:

(2,1) (3,2) (4,4) (5,8)

The y-values are:

1,2,4,8

The first term term is the term before 1,this has to be.

$a_1= \frac{1}{2}$

The common ratio is

$r = \frac{2}{1} = 2$

The nth term is given by

$a_n=a_1 {(r}^{n - 1} )$

Let's substitute the values to get,

$a_n= \frac{1}{2} \times {(2}^{n - 1} )$

This simplifies to,

$a_n= \frac{1}{2} {(2}^{n - 1} )$

3 0

3 years ago

What is 987 in expanded notation as an addition expression

Elena L [17]

Well 900 + 80 + 7 = 987

3 0

3 years ago

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The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

6 0

3 years ago