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maria [59]
3 years ago
15

What is another way to write -3 x (4+7)

Mathematics
1 answer:
atroni [7]3 years ago
8 0

Answer:

Step-by-step explanation:

-3 x (4+7)

-12 -21

=-33

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Evaluate -41-41.=<br> -8<br> 08<br> 16<br> -16
Alex Ar [27]

Answer:

are you sure those are all the options because it is -82

Step-by-step explanation:

5 0
2 years ago
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Find the length of the second base of a trapezoid with one base measuring 12 ft, a height of 4 ft, and an area of 58 square ft.
aleksandrvk [35]
The second base would be 17 feet.
To find the area of a trapezoid it is (base1 + base2) height
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3 0
3 years ago
What sequence is modeled by the graph below?
Lady bird [3.3K]

ANSWER

a_n= \frac{1}{2}( {2}^{n - 1} )

EXPLANATION

The corresponding ordered pairs from the graph are:

(2,1) (3,2) (4,4) (5,8)

The y-values are:

1,2,4,8

The first term term is the term before 1,this has to be.

a_1= \frac{1}{2}

The common ratio is

r =  \frac{2}{1}  = 2

The nth term is given by

a_n=a_1 {(r}^{n - 1} )

Let's substitute the values to get,

a_n= \frac{1}{2} \times  {(2}^{n - 1} )

This simplifies to,

a_n= \frac{1}{2} {(2}^{n - 1} )

3 0
3 years ago
What is 987 in expanded notation as an addition expression
Elena L [17]
Well 900 + 80 + 7 = 987
3 0
3 years ago
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The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1
Aleksandr-060686 [28]

Answer:

a)  The probability that a student has either a Visa card or a MasterCard is 0.71.  

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b)  In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards  is P(V \cap M)=0.03

a) Probability that a student has either a Visa card or a Master Card is given by,

P(V \cup M) = P(V) + P(M) - P(V\cap M)

P(V \cup M) = 0.63+ 0.11- 0.03

P(V \cup M) =0.74- 0.03

P(V \cup M) =0.71

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if P(A\cap B)=P(A)P(B)

For V and M to be independent the condition is satisfied,

P(V\cap M)=P(V)P(M)

Substitute the values,

0.03=0.63\times 0.11

0.03\neq 0.0693

So, V and M are not independent.

6 0
3 years ago
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