Answer:
see explaination
Explanation:
Molecular equation;
2Li3PO4(aq) + 3CaCl2(aq) >>>> Ca3(PO4)2(s) + 6LiCl(aq)
Total ionic equation; . Includes all ions ;
6Li^+(aq) + 2PO4^-3(aq) + 3Ca^+2(aq) + 6Cl^-(aq) >>>> Ca3(PO4)2(s) + 6Li^+(aq) + 6Cl^-(aq)
Net ionic equation; remove common ions from total ionic;
2PO4^-3(aq) + 3Ca^+2(aq) >>>> Ca3(PO4)2(s)
In the reaction as follows: NH2- + CH3OH → NH3 + CH3O−, NH2- is the Brønsted-Lowry base.
BRØNSTED-LOWRY BASE:
- According to Bronsted-Lowry definition of a base and acid, a base is substance that accepts an hydrogen ion or proton (H+) while an acid is a substance that donates a proton.
- According to this reaction given as follows: NH2 + CH3OH → NH3+ CH3O-
- NH2- is a reactant that accepts a hydrogen ion (H+) to become NH3+
- NH3+CH3OH is a reactant that donates hydrogen ion (H+)
- Since NH2- accepts a proton, this means that in the reaction as follows: NH2 + CH3OH → NH3 + CH3O−, NH2- is the Brønsted-Lowry base.
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Answer:
d/t=s
(divide 16)16/t= 8(divide 16)
t= 0.5 km/h²
Explanation:
Distance: 16 kilometres
Speed: 8 km/h
Time: ?
The oxidizing and reducing agent in the above redox reaction are hydrogen sulphide (H2S) and Chlorine (Cl) respectively.
<h3>What is an oxidizing and reducing agent?</h3>
An oxidizing agent is any substance that oxidizes, or receives electrons from another substance and as a result, becoming reduced.
On the other hand, a reducing agent is any substance that reduces or donates electrons to another and as a result becomes oxidized.
According to this reaction; H2S(aq) + Cl2(g) -> S(s) + 2HCI (aq)
- H2S accepts electrons from Cl2 and becomes reduced to S
- Cl2 donates electrons to H2S and becomes oxidized to HCl
Therefore, the oxidizing and reducing agent in the above redox reaction are hydrogen sulphide (H2S) and Chlorine (Cl) respectively.
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A isotope is atoms of the same element with different amount of neutrons to change the mass. They can become more stable by sharing or giving away electrons to have a stable electron shell
