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3 years ago

An isotope becomes more stable by changing the number of what?

1 answer:

3 0

A isotope is atoms of the same element with different amount of neutrons to change the mass. They can become more stable by sharing or giving away electrons to have a stable electron shell

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Plz help it’s due very soon

Setler79 [48]

Answer:

192g

Explanation:

so for this find out there moles of CH4 by moles=mass/mr

48/16=3 then use molar ratio 1:2 so times it by 2 which is 6 moles. then uses mass =moles*mr so 6*32=192g is the answer hope this helps to understand.

5 0

3 years ago

Read 2 more answers

When the NaOH dissolves, the temperature of the solution increases from 18.2 C to 24.5 C. Assuming the specific heat and density

ELEN [110]

Answer:

The heat of solution is 1.05 kJ/mol

Explanation:

NaOH → Molar mass 40 g/m

This is the mass in 1 mol

Calorimetry formula:

Q = m . c . ΔT

ΔT = T° final - T° initial = 24.5°C - 18.2°C = 6.3°C

mass = 40 g

c = 4.186 kJ/kg°C (the same as water)

So we have to convert 40 g to kg

40 g/1000 = 0.04 kg

Q = 0.04 kg . 4.186 kJ/kg°C . 6.3 °C = 1.05 kJ

7 0

3 years ago

What mass of Al2O3 is formed in the reaction of 4700 kg of aluminum? Answer in units of kg

d1i1m1o1n [39]

Answer:

2350kg of Al₂O₃

Explanation:

Step 1 : Write the balanced chemical equation:

4Al + 3O₂ → 2Al₂O₃

Step 2: Find the Ratio of Al : Al₂O₃

Al : Al₂O₃

4 : 2

2 : 1

4700: 2350

= 2350kg of Al₂O₃

6 0

2 years ago

You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q

kicyunya [14]

Answer:

3,78 mL of 12,0wt% H₂SO₄

Explanation:

The equilibrium in water is:

H₂O (l) ⇄ H⁺ (aq) + OH⁻ (aq)

The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = $10^{-7,2}$

Thus, you need to add:

[H⁺] = $10^{-7,2} - 10^{-8}$ = 5,31x10⁻⁸ M

The total volume of the pool is:

7,00 m × 18,0 m ×1,50 m = 189 m³ ≡ 189000 L

Thus, moles of H⁺ you need to add are:

5,31x10⁻⁸ M × 189000 L = 1,00x10⁻² moles of H⁺

These moles comes from

H₂SO₄ → 2H⁺ +SO₄²⁻

Thus:

1,00x10⁻² moles of H⁺ × $\frac{1 H_{2}SO_{4} moles}{2H^+ mole}$ = 5,00x10⁻³ moles of H₂SO₄

These moles comes from:

5,00x10⁻³ moles of H₂SO₄ × $\frac{98,1g}{1mol}$ × $\frac{100 gsolution}{12 g H_{2}SO_{4} }$ × $\frac{1mL}{1,080 g}$ = 3,78 mL of 12,0wt% H₂SO₄

I hope it helps!

5 0

3 years ago

What happens at the anode in an electrolytic cell?

Llana [10]

Answer:

D. Oxidation

Explanation:

In an electrolytic cell, oxidation (the loss of electrons) takes place at the anode. At the cathode reduction takes place.

A mnemonic technique that could be used is that the process that starts with a vowel (Oxidation) takes place at the place that also starts with a vowel (Anode).

7 0

2 years ago