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3 years ago

Ribosome are found ____

Chemistry

1 answer:

evablogger [386]3 years ago

6 0

It's found inside of a cell attached to the cytoplasm and attached to the endoplasmic reticulum. hope this helps

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Please help this is due tomorrow!

lbvjy [14]

I had this same question on one of are worksheets is D I can’t really explain it but the answer is D

7 0

3 years ago

In the reaction below how would adding more of product C affect the equilibrium of the system? A+B arrows both ways C+D

Shalnov [3]

Answer:

1. The reaction will proceed backward, shifting the equilibrium position to the left.

2. The reaction will proceed forward, shifting the equilibrium position to the right.

3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)

Explanation:

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3 years ago

How many grams of kclo3 can be dissolved in 100 grams of water at 30 degrees Celsius

kondaur [170]

<span>The solubility of KClO</span>₃ : ( 10.1 / 100 g water ) at 30ºC

10.1 g ------------ 100 g ( H₂O )
? g ------------- 100 g ( H₂O )

Mass of KClO₃ :

100 * 10.1 / 100

1010 / 100 = 10.1 g of KClO₃

hope this helps!

8 0

3 years ago

PLEASE HELP: To most humans, the chemical PTC tastes very bitter. The ability to taste it is a dominant trait. People who can’t

algol13

A simply because of I'm a pretty good guesser, Hope this helps.

3 0

3 years ago

Read 2 more answers

Find the density if the volume is 15 mL and the mass is 8.6 g. (5 pts)

allsm [11]

Answer:

$\large \boxed{\text{0.57 g/mL; 3.7 mL; 6.6 g; 0.366 g/mL}}$

Explanation:

1. Density from mass and volume

$\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}$

2. Volume from density and mass

$V = \text{9.7 g}\times\dfrac{\text{1 mL}}{\text{2.6 g}} = \text{3.7 mL}\\\\\text{The volume is $\large \boxed{\textbf{3.7 mL}}$}$

3. Mass from density and volume

$\text{Mass} = \text{4.1 cm}^{3} \times \dfrac{\text{1.6 g}}{\text{1 cm}^{3}} = \textbf{6.6 g}\\\\\text{The mass is $\large \boxed{\textbf{6.6 g}}$}$

4. Density by displacement

Volume of water + object = 24.6 mL

Volume of water =<u> 12.8 mL</u>

Volume of object = 11.8 mL

$\rho = \dfrac{\text{4.3 g}}{\text{11.8 mL}} = \text{0.36 g/mL}\\\text{The density is $\large \boxed{\textbf{0.36 g/mL}}$}$

Your drawing showing water displacement using a graduated cylinder should resemble the figure below.

6 0

3 years ago