All categories

3 years ago

Ribosome are found ____

Chemistry

1 answer:

evablogger [386]3 years ago

6 0

It's found inside of a cell attached to the cytoplasm and attached to the endoplasmic reticulum. hope this helps

You might be interested in

Calculate the unit cell edge length for an 78 wt% Ag- 22 wt% Pd alloy. All of the palladium is in solid solution, and the crysta

BaLLatris [955]

Answer:

The unit cell edge length for the alloy is 0.405 nm

Explanation:

Given;

concentration of Ag, $C_{Ag}$ = 78 wt%

concentration of Pd, $C_P_d$ = 22 wt%

density of Ag = 10.49 g/cm³

density of Pd = 12.02 g/cm³

atomic weight of Ag, $A_A_g$ = 107.87 g/mol

atomic weight of iron, $A_P_d$ = 106.4 g/mol

Step 1: determine the average density of the alloy

$\rho _{Avg.} = \frac{100}{\frac{C_A_g}{\rho _A_g} + \frac{C__{Pd}}{\rho _{Pd}} }$

$\rho _{Avg.} = \frac{100}{\frac{78}{10.49} + \frac{22}{12.02} } = 10.79 \ g/cm^3$

Step 2: determine the average atomic weight of the alloy

$A _{Avg.} = \frac{100}{\frac{C_v}{A _A_g} + \frac{C__{Pd}}{A _{Pd}} }$

$A _{Avg.} = \frac{100}{\frac{78}{107.87} + \frac{22}{106.4} } = 107.54 \ g/mole$

Step 3: determine unit cell volume

$V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}$

for a FCC crystal structure, there are 4 atoms per unit cell; n = 4

$V_c=\frac{4*107.54}{ 10.79*6.022*10^{23}} = 6.620*10^{-23} \ cm^3/cell$

Step 4: determine the unit cell edge length

Vc = a³

$a = V_c{^\frac{1}{3} }\\\\a = (6.620*10^{-23}}){^\frac{1}{3}}\\\\a = 4.05 *10^{-8} \ cm$ = 0.405 nm

Therefore, the unit cell edge length for the alloy is 0.405 nm

7 0

3 years ago

If you breathe fast, CO2 is If you breathe fast, C O 2 is blank and the equilibrium shifts to blank [ H 3 O + ], which raises th

brilliants [131]

Answer:

If You Breathe Fast, CO2 Is Blank The Equilibrium Shifts To Blank [H3O+], Which Raises The PH.

Explanation:

3 0

3 years ago

Plz help me I am!!!!

Soloha48 [4]

Gravity forces earth to move around the sun so A

8 0

3 years ago

Read 2 more answers

please look at the attached image i have to finish this entire unit by midnight and im stuck on this problem

djyliett [7]

$\text{H}_{2(g)}\text{ + CO}_{2(g)}\text{ }\rightleftarrows\text{ H}_2\text{O}_{(g)}\text{ + CO}_{(g)}$

The reaction is balanced

The equilibrium constant is defined as the concentration ratio of the products and reactants. They are not considered pure solids and liquids.

$\text{ K}_{eq}=\frac{\lbrack\text{CO}\rbrack\lbrack\text{ H}_2\text{O}\rbrack}{\lbrack\text{ H}_2\rbrack\lbrack\text{ CO}_2\rbrack}$

So the answer is option B.

4 0

2 years ago

1. Which number is more accurate if the correct number is 3.5. Is it 3.1, 3.3, 3.6, or 4.0?

natta225 [31]

Seems to be 3.6 since it’s closer by 1, As for 4.0 it would be 5 more.

6 0

3 years ago

Read 2 more answers