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erastovalidia [21]
2 years ago
9

3. Determine the value of x if:

Mathematics
1 answer:
pishuonlain [190]2 years ago
6 0

Step-by-step explanation:

3.1.

your question

75x-25=5x+125

collect like terms

70x=150

Divide both side by the coefficient of x

70x/70=150/70

70 ti cancel 70 on x side to leave x alone

:. x=150/70 or 2.14

3.2.

6×(3x-2)=7×(x+3)

multiply by the bracket

18x-12=7x+21

collect like terms

18x+7x=21+12

25x=33

divide by the coefficient of x

25x/25=33/25

x=33/25 or 1.32

3.3.

10/x-3=8

cross multiply(know that 8 is /1)

x‐3×8=10×1

8x-24=10

8x=10+24

8x=34

divide both sides by coefficient of x

8x/8=34/8

8x=34/8 or 4.25

3.4.

x+7=5x-13

collect like terms

7+13=5x-x

20=4x

divide both sides by the coefficient of x

20/4=4x/4

5=x

:.x=5

3.5.

20x+4=4x-46

collect like terms

20x-4x=-46-4

16x=-52

divide both sides by the coefficient of x

16x/16=-52/16

:.x=52/16 or 3.25

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Step-by-step explanation:

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Step-by-step explanation:

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1. What are the opposite and absolute value of: a) 7.2 ____,____ b) -3.5 ____, ____ c) 5 ½ ____,____
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Esta pregunta esta incompleta

Pregunta completa

Se necesitan conductores voluntarios para llevar a 80 estudiantes al juego de béisbol del campeonato. Los conductores cuentan con automóviles, con capacidad para 4 estudiantes, o camionetas, con capacidad para 6 estudiantes. La ecuación describe la relación entre la cantidad de automóviles y la cantidad de camiones que pueden transportar exactamente 80 estudiantes.

Seleccione todas las afirmaciones que sean verdaderas sobre la situación.

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c) Si van 6 coches y van 11 furgonetas, habrá espacio adicional.

d) 10 coches y 8 furgonetas no son suficientes para transportar a todos los estudiantes.

e) Si pasan 20 autos, no se necesitan camionetas.

f) 8 furgonetas y 8 coches son números que cumplen con las limitaciones en esta situación.

Answer:

La opción b, e y f.

Step-by-step explanation:

Pasando por las opciones dadas:

c = coches que pueden llevar a 4 estudiantes

v = furgonetas con capacidad para 6 estudiantes

a) Si van 12 coches, se necesitan 2 furgonetas.

= 12 (4) + 2 (6)

= 48 + 12

= 60

60 ≠ 80

La opción a es incorrecta

b) c = 14 y v = 4 son un par de soluciones de la ecuación.

14 (4) + 4 (6)

56 + 24 = 80 estudiantes

La opción b es correcta

c) Si van 6 coches y van 11 furgonetas, habrá espacio adicional.

Por lo tanto:

5 (4) + 11 (6)

= 20 + 66

= 86.

86 es mayor que 80, la opción c es correcta, habría un espacio adicional para 6 estudiantes.

d) 10 coches y 8 furgonetas no son suficientes para transportar a todos los estudiantes.

Por lo tanto:

10 (4) + 8 (6)

40 + 48

= 88

e) Si pasan 20 autos, no se necesitan camionetas.

20 (4) = 80 estudiantes

La opción e es correcta

f) 8 furgonetas y 8 coches son números que cumplen con las limitaciones en esta situación.

8 (6) + 8 (4)

= 48 + 32

= 80 estudiantes.

La opción b es correcta

Por lo tanto, la ecuacióna que describe la relación entre la cantidad de automóviles y la cantidad de camiones que pueden transportar exactamente 80 estudiantes es la opción b, e y f.

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