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3 years ago

15

Evaluate the expression if m = -4, n = 1, p = 2, 9 = -6, r = 5, and t = -2. |16+4(3q + p)|

2 answers:

swat323 years ago

7 0

Answer:

720

Step-by-step explanation:

|16+4(3(-6)+(2)|

|20(-18*2)|

|20*-36|

|-720|

720

Sonbull [250]3 years ago

5 0

Step-by-step explanation:

$|16 + 4(3q + p)| \\ p = 2 \\ q = - 6 \\ then \\ = |16 + 4(3 \times - 6 + 2)| \\ = |16 + 4( - 18 + 2)| \\ = |16 + 4( - 16)| \\ |16 + - 64| \\ = | - 48| \\ take \: out \: side \: of \: mode \: then \: it \: become \: = 48 \\ \\ thank \: you$

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Write the number below in scientific notation, incorporating what you know about significant digits. 67,890,000

SVETLANKA909090 [29]

The answer would be: 67.89 x 10^6

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Thus, only the significant numbers left in the equation:

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2 years ago

Help math<br>look at pic

Sloan [31]

Answer: $\Large\boxed{(-4,~-3)~\text{and}~(-2,~1)}$

Step-by-step explanation:

<u>Given the system of equation</u>

$1)~y=-(x+2)^2+1$

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$y=-x^2-4x-4+1$

$y=-x^2-4x-3$

<u>Current System</u>

$1)~y=-x^2-4x-3$

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<u>Substitute the y value of the 1) equation with the 2) equation</u>

$2x+5=-x^2-4x-3$

<u>Add ( x² + 4x + 3) on both sides</u>

$2x+5+(x^2+4x+3)=-x^2-4x-3+(x^2+4x+3)$

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<u>Combine like terms</u>

$x^2+2x+4x+5+3=0$

$x^2+6x+8=0$

<u>Factorize the quadratic equation</u>

$(x+4)(x+2)=0$

$x=-4~\text{or}~x=-2$

<u>Substitute the x values into one of the equations to find the y value</u>

$y=2x+5$

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$y=2(-2)+5=-4+5=1$

<u>Therefore, the two solutions are:</u>

$\Large\boxed{(-4,~-3)~\text{and}~(-2,~1)}$

Hope this helps!! :)

Please let me know if you have any questions

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