Assume that the radius of the circle is 1.
The diagonal of the square is 2. By the Pythagorean Theorem, the side of the square of a right triangle will be 2/sqrt(2).
Finally, the ratio of the square to the circle, in area, will be
(2/sqrt(2))^2 : pi*(1)^2 = 2 : pi
We can conclude that the white area is about 35%.
For this case we must indicate which of the equations shown can be solved using the quadratic formula.
By definition, the quadratic formula is applied to equations of the second degree, of the form:

Option A:

Rewriting we have:

This equation can be solved using the quadratic formula
Option B:

Rewriting we have:

It can not be solved with the quadratic formula.
Option C:

Rewriting we have:

This equation can be solved using the quadratic formula
Option D:

Rewriting we have:

It can not be solved with the quadratic formula.
Answer:
A and C
2[4 − 7(3x + 4y)] + 2[3x(−2y)]
2[4 - 21x -28y] + 2[-6xy]
8 - 42x - 56y -12xy
the perimeter of given rectangular garden is (8 - 42x - 56y -12xy).
Answer:
-20c-160
Step-by-step explanation:
-10(9c-7c+8)-80
-10(2c+8)-80
-20c-80-80
-20c-160