Balanced chemical equation for reaction of hydronium ions with calcium carbonate will be as follows:
2H3O+ (aq) + CaCO3 (s) => Ca2+ (s) + 3H2O (l) + CO2 (g)
In this balanced chemical equation, acidic aqueous solution of hydronium ion (H3O+) reacts with calcium carbonate salt (CaCO3) resulting in the formation of calcium cation (Ca2+) an alkali, that results in neutralization of excessive acid. It also forms liquid water (H2O) along with liberation of carbon dioxide gas (CO2). All acids stronger than hydrogen carbonate, provide their calcium salts dissolved in water yielding carbon dioxide, because a bare hydrogen ion has no chance of surviving in water.
To balance this chemical equation, 2 molecules of hydronium ions react with 1 molecule of calcium carbonate resulting in formation of 1 molecule of calcium cation, 3 molecules of water and 1 molecule of carbon dioxide. The reaction proceeds at room temperature.
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Answer:
12 amu or 12 g.
Explanation:
One mole of 12C = one 12c atom. The mass of one carbon-12 atom is 12.000 amu.
Answer:
The limiting reactant is the 6.279 g of
Explanation:
We have to start with the <u>reaction</u> between sodium carbonate () and the Nickel (II) Chloride (), so:
We will have a <u>double replacement reaction</u>. Now we have to <u>balance</u> the reaction, so:
The next step is the <u>calculation of the moles for each reactive</u>. For we have use the <u>molarity equation</u>:
For the calculation of moles of we have to use the <u>molar mass</u> of the compound (129.59 g/mol):
The next step is the division of each mole value by the <u>coefficient of each reactive</u> of the balance reaction. In this case <u>we have "1" for each reactive</u>, so:
The final step is to <u>choose the smallest value</u>. In this case is the value that correspond to . Therefore is the limiting reactive.