Answer:
Calcite
Explanation:
The chart shows that calcite is higher than gypsum, but is lower than apatite. Therefore meaning that it can scratch gypsum But not able to the same to apatite.
When the dissociation equation of NH3 is:
NH3(aq) + H2O ↔ NH4(aq) + OH-(aq)
when Kb =(1.8 x 10^-5)
and when PH+POH= 14
∴ POH = 14 -11= 3
when POH = -㏒[OH]
∴[OH] = 0.001
when [OH] = [NH4+] = 0.001
when Kb = [NH4+][OH-]/[NH4OH]
by substitution:
1.8 x 10^-5 = (0.001)^2 / [ NH4OH]
∴[NH4OH] = 0.06 M
Answer:
There is no formation of shmoos
Explanation:
If the hypothesis that says "Fus3 kinase is required for the signal transduction pathway leading shmoo formation" is correct, then a strain with a deletion Fus3, is not going to render Fus3 kinase, at least active. By this reason, there will not be shmoo formation
Answer:
1.98 M
Explanation:
Given data
- Initial volume (V₁): 93.2 mL
- Initial concentration (C₁): 2.03 M
- Volume of water added: 3.92 L
Step 1: Convert V₁ to liters
We will use the relationship 1 L = 1000 mL.
Step 2: Calculate the final volume (V₂)
The final volume is the sum of the initial volume and the volume of water.
Step 3: Calculate the final concentration (C₂)
We will use the dilution rule.
The graphite of the pencil sits on top of the paper and won't affect the results. If you use ink, it will seep into the paper and itself be subjected to the chromatographic process.
Hope this helped :)