The grams of NaOH that are present in 247.0 ml of a 0.300M NaOH solution is 2.964 grams
<u><em>calculation</em></u>
Step 1: find moles of NaOH
moles = molarity x volume in liters
volume in liters = 247.0 /1000 = 0.247 liters
molarity = 0.300 M = 0.300 mol/l
moles = 0.300 mol/l x 0.247 =0.0741 moles
step 2: find mass of NaOH
mass= moles x molar mass
The molar mass of NaOH = 23 +1 +16= 40 g/mol
mass=0.0741 moles x40 g/mol =2.964 grams
Answer:
14 mL
Explanation:
To prepare a solution by a concentrated solution, we must use the equation:
C1xV1 = C2xV2, where <em>C</em> is the concentration, <em>V</em> is the volume, 1 is the initial solution and 2 the final solution.
The final solution must have 2 mL and a concentration of 350 pg/mL, and the initial solution has a concentration of 50 pg/mL.
Then:
50xV1 = 350x2
50xV1 = 700
V1 = 700/50
V1 = 14 mL
Most elements tend to have the same number of electrons and protons. This gives the element a neutral charge, aka no charge at all.
Here is an example:- Flourine
7 electrons and 7 protons
Answer:
Heather has to do a titration with the acid-base reaction. She would need a complete buret assembly that contains, a buret, a buret clamp and a ringstand. She would also need an erlenmeyer flask and of course, a volumetric pipet with its pipet bulb.
Explanation: