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DanielleElmas [232]
3 years ago
11

Revision has a atoMic number of 37 and a mass number of 85. HIW many protons, neutrons and electrons does an ion of rubidium wit

h a 1+ charge have
Chemistry
1 answer:
EleoNora [17]3 years ago
6 0

Answer: 37 protons, 48 neutrons, and 36 electrons.

Explanation: I assume "Revision" is Rubidium. It is atomic number 37, so it has 37 protons. It's atomic mass is 85, so it has an average of (85-37) = 48 neutrons. It has a charge of +1, so one electron of the original 37 has left.

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What is the cause of change over time in a population?
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3 years ago
What is the pH of the solution formed when 25 mL of 0.173 M NaOH is added to 35 mL of 0.342 M HCl?
Ugo [173]

Answer:

0.89

Explanation:

You are mixing an acid and a base, so there will be a neutralization reaction.

One of the reactants will be in excess, so we must determine its concentration and then calculate the pH.

<em>Moles of NaOH </em>

Moles of NaOH = 25 × 0.173

Moles of NaOH = 4.32 mmol

===============

<em>Moles of HCl </em>

Moles of HCl = 35 × 0.342

Moles of HCl = 12.0 mmol

===============

<em>Amount of excess reactant </em>

              NaOH + HCl ⟶ NaCl +H₂O

<em>n</em>/mmol:   4.32      12.0

The 4.32 mmol of NaOH reacts completely with 4.32 mmol of HCl.

Excess HCl = 12.0 – 4.32

Excess HCl = 7.6 mmol

===============

<em>Concentration of the excess HCl </em>

Total volume = 25 + 35

Total volume = 60 mL

<em>c </em>= millimoles HCl/millilitres HCl

<em>c</em> = 7.6/60

<em>c</em> = 0.13 mol/L

===============

<em>Calculate the pH </em>

The HCl dissociates completely to hydronium ions, so

[H₃O⁺] = 0.13 mol·L⁻¹

pH = -log[H₃O⁺]

pH = -log0.13

pH = 0.89

8 0
3 years ago
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