Tetraamminedichloridoiron(3) nitrate
To begin with, the equation given is not correct.
Correct equation is : CaCO3 + HCl ---> CaCl2 + H2O + CO2
It's CaCl2 not CaCl because Ca has a valency of 2
LHS RHS
CaCO3 + HCl ---> CaCl2 + H2O + CO2
First of all, to balance the equation you must look at the number of atoms on each side of the equation.
we have 2 H on the RHS and 1 H on the LHS. So, we put a 2 on the LHS
CaCO3 + 2HCl ---> CaCl2 + H2O + CO2
Check for the LHS: 1 Ca, 1 C, 3 O, 2 H & 2 Cl on the LHS
Now check for the RHS: 1 Ca, 2 Cl, 2 H, 1 C & 3 O
Hope it helped!
Attraction between a cation in one element and an anion in the other element
Answer:
sodium hydroxide and hydrochloric acid is the reactants
The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.
<u>Explanation:</u>
Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.
![\text {Molality}=\frac{\text {Moles of solute}}{\text {Mass of solvent}}](https://tex.z-dn.net/?f=%5Ctext%20%7BMolality%7D%3D%5Cfrac%7B%5Ctext%20%7BMoles%20of%20solute%7D%7D%7B%5Ctext%20%7BMass%20of%20solvent%7D%7D)
As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.
Hence, ![\text { molality }=\frac{1.34}{2.47}= 0.54 \mathrm{M}](https://tex.z-dn.net/?f=%5Ctext%20%7B%20molality%20%7D%3D%5Cfrac%7B1.34%7D%7B2.47%7D%3D%200.54%20%5Cmathrm%7BM%7D)
Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.